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IrinaK [193]
3 years ago
9

36. What is the solution to x+3 = -6?HELP! answer if you can!​

Mathematics
2 answers:
Arlecino [84]3 years ago
8 0

Answer:

x = -9

Step-by-step explanation:

subtract 3 from both sides

x = -9

Furkat [3]3 years ago
3 0

Answer:

x = -9

Step-by-step explanation:

x + 3 = -6

Subtract 3 from both sides.

x + 3 - 3 = -6 - 3

x = -9

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A pump moves 42 gallons in seven minutes.Find the unit rate.
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Answer:

6 GALLONS PER MINUTE

Step-by-step explanation:

42/7=6

6 gallons per minute

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3 years ago
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[63, 9] [14, 5] [21, 3] [26, ?]<br><br> What is the unknown in this pattern, show working please.
ehidna [41]

Look :

6 + 3 = 9 ===》 [ 63 , 9 ]

1 + 4 = 5 ===》 [ 14 , 5 ]

2 + 1 = 3 ===》 [ 21 , 3 ]

2 + 6 = 8 ===》 [ 26 , 8 ]

8 0
3 years ago
PLEASE HELP!! Find the value of x.
grigory [225]

Answer:

choice 1) x = 4

Step-by-step explanation:

∠2 = ∠6

4x+44 = 6x+36

reduce:

2x = 8

x = 4

3 0
3 years ago
Steve has three times as many quarters as half-dollars. The coins total $13.75. How many total coins does he have, how would you
statuscvo [17]
Hello,
Let assume x the number of half-dollars3x is the number of quarters.
The coins total $13.75.
0.50 *x+ 0.25 *3x=13.75\\&#10;&#10;\Rightarrow\  \dfrac{x}{2}+ \dfrac{3x}{4}=13.75\\&#10;&#10;\Rightarrow\  \dfrac{2x}{4}+ \dfrac{3x}{4}=13.75\\&#10;&#10;\Rightarrow\  \dfrac{5x}{4}=13.75\\&#10;&#10;\Rightarrow\  5x=4*13.75\\&#10;&#10;\Rightarrow\  5x=55\\&#10;&#10;\Rightarrow\  x=11\\&#10;&#10;

11 is the number of half-dollars

33 is the number of quarters.
8 0
3 years ago
Find the projection of u = &lt;–6, –7&gt; onto v = &lt;1, 1&gt; a. &lt;-13/2,-13/2&gt; b. &lt;39,91/2&gt; c. &lt;-13/1764,-13/17
Alexandra [31]
<h2>Answer:</h2>

a. <-13/2,-13/2>

<h2>Step-by-step explanation:</h2>

The projection of a vector u onto another vector v is given by;

proj_vu = (\frac{u.v}{|v|^2})v               ----------------(i)

Where;

u.v is the dot product of vectors u and v

|v| is the magnitude of vector v

Given:

u = <-6, -7>

v = <1, 1>

These can be re-written in unit vector notation as;

u = -6i -7j

v = i + j

<em>Now;</em>

<em>Let's find the following</em>

(i) u . v

u . v = (-6i - 7j) . (i + j)

u . v = (-6i) (1i) + (-7j)(1j)          [Remember that, i.i = j.j = 1]

u . v = -6 -7 = -13

(ii) |v|

|v| = \sqrt{(1)^2 + (1)^2}

|v| = \sqrt{2}

<em>Substitute these values into equation (i) as follows;</em>

proj_vu = [\frac{-13}{(\sqrt{2}) ^2}][i + j]

proj_vu = \frac{-13}{2} [i + j]

This can be re-written as;

proj_vu = \frac{-13}{2}i + \frac{-13}{2}j

proj_vu =

5 0
3 years ago
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