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Vera_Pavlovna [14]
3 years ago
8

The total cost after tax to repair Kimber's cracked phone screen is represented by 0.04(30h) + 30h, where h represents the numbe

r of hours it takes to repair kimber's phone. what part of the expression represents the amount of tax she must pay? EXPLAIN YOUR ANSWER IN COMPLETE SENTENCES FOR ALL MY POINTS
Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
6 0

In this equation there are few key numbers, thankfully XD, so it does not take too long to figure out that the 0.04 is clearly a tax on the repairs as 30h is representing the hours spent repairing Kimber's phone.

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Consider a deck with 2626 black and 2626 red cards. You draw one card at a time and you can choose either guess on whether it is
gregori [183]

The maximum earning is v(r,b)

Let v(r,b) be the expected value of the game for the player, assuming optimal play, if the remaining deck has r red cards and b black cards.

Then v(r,b) satisfies the recursion

and

The stopping rule is simple: Stop when v(r,b)=0.

To explain the recursion . . .

If r,b>0, and the player elects to play a card, then:

  • The revealed card is red with probability \frac{r}{r+b}, and in that case, the player gets a score of +1, and the new value is V(r-1,b)
  • The revealed card is black with probability \frac{b}{r+b}, and in that case, the player gets a score of −1, and the new value is V(r,b-1)

Thus, if r,b>0, electing to play a card yields the value f(r,b).

But the player always has the option to quit, hence, if r,b>0, we get v(r,b)=max(0,f(r,b)).

Implementing the recursion in Maple, the value of the game is

v(26,26)=41984711742427/15997372030584

v(26,26)  ≈2.624475549

and the optimal stopping strategy is as follows . . .

  • If 24≤b≤26, play while r≥b−5.
  • If 17≤b≤23, play while r≥b−4.
  • If 11≤b≤16, play while r≥b−3.
  • If 6≤b≤10, play while r≥b−2.
  • If 3≤b≤5, play while r≥b−1.
  • If 1≤b≤2, play while r≥b.
  • If b=0, play while r>0.  

So, The maximum earning is v(r,b)

Learn more about PROBABILITY here

brainly.com/question/24756209

#SPJ4

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