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Lelu [443]
3 years ago
12

An adolescent presents to a community clinic for treatment of vulvar lesions associated with type 2 herpes simplex. the nurse sh

ould:
Biology
1 answer:
notka56 [123]3 years ago
6 0

<span>First the nurse must take the adolescent to the examination room.  The rationale for this is to provide privacy to the client.  The next step is to give the adolescent a literature containing details of type 2 herpes simplex.  Maintaining the patient’s confidentiality is a must as well.</span>

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The appropriate order for the basic steps of protein synthesis are: A. The elongation reaction transfers the peptide chain from
Hoochie [10]

Answer:

The appropriate order for the basic steps of protein synthesis are listed below

Explanation:

First step  D The large ribosomal subunit joins the initiation complex preparing it for elongation stage.

Second step C Binding of mRNA by small Sub unit followed by association of a particular initiator aminoacyl tRNA that recognizes the first codon.

Third step   B The P site is occupied by peptidyl tRNA carrying the growing polypeptide chain.

Fourth step A The elongation reaction transfers the peptide chain from the peptidyl  tRNA in the p site to the aminoacyl tRNA in the A site.

Fifth step   E The new longer Peptidyl tRNA moves from A site into the p site as the ribosome moves one codon further along the mRNA.

6 0
3 years ago
Assume that a black guinea pig crossed with an albino guinea pig produced 5 black offspring. when the albino was crossed with a
Radda [10]
As a matter of terminology, albino guinea pig actually refers to a white fur guinea pig, whose genotype is homozygous recessive (bb).

If it crossed with a black fur guinea pig and gave 5 black fur offsprings, there is a good chance that the black fur parent is homozygous dominant (BB).
The Punnett square would be as follows:

       B      B
b     Bb   Bb
b     Bb   Bb
So they are all heterozygous black fur offsprings.

However, it is not impossible that the black fur parent be heterozygous, namely

       B      b
b    Bb   bb
b    Bb   bb

Giving a 50% chance on each colour.  Thus it is possible (with probability 1/32) that all five offsprings are heterozygous black fur if one of the parents was heterozygous.

In the second case, a homozygous recessive and a homozygous dominant parent will never give a white offspring.  So it is sure that the black fur parent is heterozygous, with the following Punnett square:

       B      b
b     Bb   bb
b     Bb   bb

With a 50% probability for each of Bb (black fur) and bb (white fur).
the distribution 4,3 demonstrates this perfectly.
6 0
3 years ago
Living things contain units of structure and function that arise from preexisting units. This statement best describes the
galina1969 [7]

Answer:

cell theory

Explanation:

cells are the basic unit of structure in organism

5 0
4 years ago
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WILL MARK YOU BRAINLIEST
Olenka [21]
Which question is it there are multiple ???
8 0
3 years ago
I need help with this question ASAP!!
grin007 [14]

Answer: it’s about like lifecycle and stuff

Explanation:

7 0
3 years ago
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