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ycow [4]
3 years ago
7

The perimeters of similar triangles are in the same ratio as the corresponding sides

Mathematics
1 answer:
wariber [46]3 years ago
3 0

Answer:

Always

Step-by-step explanation:

Suppose you have triangle ABC with side lengths a, b, c. Suppose that is similar to triangle DEF with side lengths d, e, f.

Now, let k be the ratio of corresponding sides ...

  k = d/a

Because the same factor applies to all sides, we also have ...

  k = e/b = f/c

That is, if we multiply by the denominators of each of these fractions, we get ...

  • d = a·k
  • e =b·k
  • f = c·k

The perimeter of ΔABC is ...

   perimeter(ABC) = a + b + c

The perimeter of ΔDEF is ...

  perimeter(DEF) = d + e + f = a·k + b·k + c·k

  perimeter(DEF) = k(a + b + c) = k·perimeter(ABC)

  k = perimeter(DEF)/perimeter(ABC)

That is, the perimeters are in the same ratio as corresponding sides.

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The number of potholes in any given 1 mile stretch of freeway pavement in Pennsylvania has a bell-shaped distribution. This dist
alexira [117]
<h3>Answer:   83.85%</h3>

This value is approximate.

==========================================================

Explanation:

Let's compute the z score for x = 40

z = (x-mu)/sigma

z = (40-47)/7

z = -1

We're exactly one standard deviation below the mean.

Repeat these steps for x = 68

z = (x-mu)/sigma

z = (68-47)/7

z = 3

This score is exactly three standard deviations above the mean.

Now refer to the Empirical Rule chart below. We'll add up the percentages that are between z = -1 and z = 3. This consists of the two pink regions (each 34%), the right blue region (13.5%) and the right green region (2.35%). These percentages are approximate.

34+34+13.5+2.35 = 83.85

<u>Roughly 83.85%</u> of the one-mile roadways have between 40 and 68 potholes.

5 0
2 years ago
Dwayne is having a birthday party with a total of 37 people (including himself). He needs to buy enough cases of soda to have 2
svet-max [94.6K]

Answer:

I do not know

Step-by-step explanation:

5 0
3 years ago
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marissa [1.9K]

Answer:

option b)

tan²θ + 1 = sec²θ

Step-by-step explanation:

The Pythagorean trigonometric identity is a trigonometric identity expressing the Pythagorean theorem in terms of trigonometric functions.

hypotenuse² = height² + base²

Given in the questions are some pythagorus identities which except of b) are all incorrect as explained below.

<h3>1)</h3>

sin²θ + 1 = cos²θ     incorrect

<h3>sin²θ + cos²θ = 1 correct</h3><h3 /><h3>2)</h3>

by dividing first identity by cos²θ

sin²θ/cos²θ + cos²θ/cos²θ = 1/cos²θ

<h3>tan²θ + 1 = sec²θ  correct</h3><h3 /><h3>3)</h3>

1 - cot²θ = cosec²θ  incorrect

by dividing first identity by sin²θ

sin²θ/sin²θ + cos²θ/sin²θ = 1/sin²θ

<h3>1 + cot²θ = cosec²θ correct</h3><h3 /><h3>4)</h3>

1 - cos²θ  = tan²θ

not such pythagorus identity exists

4 0
3 years ago
Read 2 more answers
What is the ratio 3:4 of 21?
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3-----4

3-----4

3-----4

Total (Left): 9

Total (Right): 12

-------------------

Total (Left) + Total (Right) = 9 + 12 = 21

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3 years ago
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