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3 years ago

The original cost was $50 and the new cost is $60

Mathematics

1 answer:

ale4655 [162]3 years ago

7 0

There is no question. But I'd gladly help if you had a question!

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Which problem can be represented by the equation 49y−8=89?

sasho [114]

The first one is the answer

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3 years ago

How do you write out 3 1/4 times 24

solmaris [256]

The answer is 28 because 1/4 is equivalent to .25 so 3.25 x 24 equals 28.

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3 years ago

What is a factor can you ples tell me what a factor is

scoundrel [369]

Answer:

the numbers being multiplied in an equation

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3 years ago

Sabiendo que cada persona unos 4 500 000 glóbulos rojos por milímetro cúbico y que su cantidad de sangre es de 5 litros A) Que l

love history [14]

Answer:

Part A) distance covered by the aligned red cells is: 180000 Km

Part B) 8000000 bacteria (8 million bacteria)

Step-by-step explanation:

Part A)

Let's first find the total number of red cells that the person has in the 5 liters, knowing that there are 4,500,000 of them in a cubic millimetre:

Since 1 liter contains 1,000,000 cubic millimetres, then, in 5 liters there must be 5 times that number of cubic millimetres. That is a total of 5,000,000 cubic millimetres.

Since in each cubic millimetre there are 4,500,000 red cells, then the number of red cells in the 5 liters must be the product of these two quantities:

4,500,000 x 5,000,000 = 22,500,000,000,000 red blood cells.

Now, to find the distance they will cover aligned one after the other, knowing that their average diameter is 0.008 mm is:

22,500,000,000,000 x 0.008 mm= 180000000000 mm

$22.5\,\,10^{12} * 8\,\,10^{-3}=1.8\,\,10^{11}$ mm

In order to convert this distance into Km as requested, we use the fact that 1 mm = 0.000001 Km, or using exponents in base ten:

1 mm = $10^{-6}\,\,Km$

Then, the distance covered in kilometers is:

$1.8\,\,10^{11}\,*\,10^{-6} \,\,Km=1.8\,\,10^{5}\,\,Km=180000\,\,Km$

Part B)

The vaccine contains a total of $10^8$ bacteria per $cm^3$

In order to find how many bacteria we have in 80 $mm^3$ of the vaccine, we first need to convert 80 $mm^3$ into $cm^3$ :

$80\,\, mm^3 = 0.08 \,\,cm^3$

Then, if in one $cm^3$ there is $10^8$ bacteria, in $0.08\,\,cm^3$ there would be: $0.08\,*\,10^8$ bacteria. That is: $8\,\,10^6$ bacteria = 8000000 bacteria (eight million bacteria)