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2 years ago

100 points to whoever helps the fastest.

Mathematics

2 answers:

jonny [76]2 years ago

6 0

Answer:

cos theta = 8/17

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos theta = adjacent side/ hypotenuse

cos theta = 8/17

Liono4ka [1.6K]2 years ago

5 0

Answer:

8/17

Step-by-step explanation:

adjacent side (height) = 8

hypotenuse = 17

Let theta be called 'x'

cos x= adjacent side (height)/hypotenuse

= 8/17

Hope this helps!

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Joey and Armando live on the same st as the park. The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando'

AleksandrR [38]

Let's start by assuming Armando's house is between Joey's and the park.

Let $x$ be the distance Joey walked to Armando's house.

The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando's home. Then Joey and Armando walk 3/5 mile to the park.

 $\dfrac{9}{10} = x + \dfrac{3}{5}$

$x = \dfrac{9}{10} - \dfrac{3}{5} = \dfrac{9}{10} -\dfrac{6}{10} = \dfrac{3}{10}$

That's probably the answer they're looking for. But what if the park is between Joey and Armando's houses or Joey is between the park and Armando? (The latter isn't really possible with the given distances.)

Let $a, b, c$ be the distances between three collinear points like we have here. Our equation is really a few equations in one, something like

$\pm a \pm b = \pm c$

Let's get rid of the plus/minuses. Squaring,

$a^2 + b^2\pm 2ab = c^2$

$\pm 2ab = c^2-a^2-b^2$

$4a^2b^2 = (c^2-a^2-b^2)^2$

For us, that's a quadratic equation for $c^2$

$4(9/10)^2(3/5)^2= (c^2-(9/10)^2 - (3/5)^2)^2$

I'll skip right to the solutions,

$c^2=\dfrac{9}{100} \textrm{ or } c^2=\dfrac{9}{4}$

$c=\dfrac{3}{10} \textrm{ or } c=\dfrac{3}{2}$

We could have gotten the 3/2 just by adding 9/10+3/5 but this was more fun.

6 0

3 years ago

Can someone please help me on this question I will give brainliest

xz_007 [3.2K]

Answer:

A) 3 in

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Geometry

Surface Area of a Sphere: SA = 4πr²
Diameter: d = 2r

Step-by-step explanation:

Step 1: Define

SA = 23 in²

Step 2: Find r

Substitute [SAS]: 23 in² = 4πr²
Isolate r term: 23 in²/(4π) = r²
Isolate r: √[23 in²/(4π)] = r
Rewrite: r = √[23 in²/(4π)]
Evaluate: r = 1.35288 in

Step 3: Find d

Substitute [D]: d = 2(1.35288 in)
Multiply: d = 2.70576 in
Round: d ≈ 3 in

4 0

2 years ago

Would my answer choice be correct? ( There is a photo)

Leni [432]

Answer:

yes I believe so. best of luck

8 0

2 years ago

A mine elevator was at a depth of -120 feet. After 15 seconds, the mine elevator was at a depth of -30 feet. Which expression sh

KonstantinChe [14]

-120 + -30 = 90. 90/15 = 6
Answer ; 6mph

8 0

3 years ago

Suppose z equals f (x comma y ), where x (u comma v )space equals space 2 u plus space v squared, y (u comma v )space equals spa

barxatty [35]

$z=f(x(u,v),y(u,v)),\begin{cases}x(u,v)=2u+v^2\\y(u,v)=3u-v\end{cases}$

We're given that $f_x(6,1)=3$ and $f_y(6,1)=-1$ , and want to find $\frac{\partial z}{\partial v}(1,2)$ .

By the chain rule, we have

$\dfrac{\partial z}{\partial v}=\dfrac{\partial z}{\partial x}\dfrac{\partial x}{\partial v}+\dfrac{\partial z}{\partial y}\dfrac{\partial y}{\partial v}$

and

$\dfrac{\partial x}{\partial v}=2v$

$\dfrac{\partial y}{\partial v}=-1$

Then

$\dfrac{\partial z}{\partial v}(1,2)=\dfrac{\partial z}{\partial x}(6,1)\dfrac{\partial x}{\partial v}(1,2)+\dfrac{\partial z}{\partial y}(6,1)\dfrac{\partial y}{\partial v}(1,2)$

(because the point $(x,y)=(6,1)$ corresponds to $(u,v)=(1,2)$ )

$\implies\dfrac{\partial z}{\partial v}(1,2)=3\cdot2\cdot2+(-1)\cdot(-1)=\boxed{13}$

4 0

3 years ago