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Jet001 [13]
3 years ago
8

the area of a triangular block is 64 sq in. if the base os the triangle is twice the height, how long are the base and the heigh

t of the triangle
Mathematics
1 answer:
Nookie1986 [14]3 years ago
4 0
------------------------------------------------------
Define x :
------------------------------------------------------
Let the height be x.
Height = x
Length = 2x

------------------------------------------------------
Solve for x:
------------------------------------------------------
Area of triangle = 1/2 x base x height
64 = 1/2 (x)(2x)
x² = 64
x = √64
x = 8

------------------------------------------------------
Find the height and the length:
------------------------------------------------------
Height = x = 8 in
Length = 2x = 2(8) = 16 in

---------------------------------------------------------------------------
Answer: The base is 16 in and the height is 8 in.
---------------------------------------------------------------------------
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Mr. Gurung sold a bicycle for Rs 18,816 and made a profit of 12%. if he wants
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Answer:

Rs. 23520

Step-by-step explanation:

Given that :

At 12% profit ; sales price = 18,816

At (12 + 3)% profit ; sales price = x

Hence,

0.12 = 18,816

0.15 = x

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0.12x = 0.15 * 18816

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If the domain (or pre-image) is (-4, -2), (5, 9), (-6, 2) and the range (or image) is
Neko [114]

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This is equivalent to 270 degrees counterclockwise

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The diagram below shows an example of this for the point (-4,-2) rotating to (-2, 4). The center of the rotation is the origin (0,0).

5 0
2 years ago
Find the product (3x-9)^2
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4 0
3 years ago
Abag contains 2 Snicker
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Step-by-step explanation:

3 0
3 years ago
While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0
4 years ago
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