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Stels [109]
2 years ago
6

A surveyor wants to know how many shoppers at a mall like to read books. He surveys 100 people coming out of a bookstore at the

mall.
Why is the sample biased?


It is unlikely that people who shop in bookstores are interested in surveys.

The surveyor did not sample the entire population at the mall.

There are not enough people in the sample.

People who shop in bookstores are likely to read more books than those who do not.
Mathematics
1 answer:
Alisiya [41]2 years ago
8 0
D. People who shop in bookstores are likely to read more books than those who do not.
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If shamans has 3&1/3 cups of flour to make cupcakes. If she needs 1/13 cup of flour to make one cupcake how many full cupcak
Kobotan [32]

Answer:

43.3 cupcakes

Step-by-step explanation:

If shamans has 3&1/3 cups of flour to make cupcakes. If she needs 1/13 cup of flour to make one cupcake how many full cupcakes can she make

From the above question

1/ 13 cup = 1 cup cake

3 1/3 cups = x

Cross Multiply

1 /13 × X = 3 1/3 × 1

x = 10/3 ÷ 1 /13

x = 10/3 × 13/1

x = 130/3

x = 43.333333333 cupcakes

8 0
2 years ago
Is 8/11 greater, less than or equal to 0.7
jeka94

Answer: It is greater ..


Step-by-step explanation:

8/11 = 0.727

70/100 = 0.7

6 0
3 years ago
Read 2 more answers
What is BE ?<br> Please explain it in full dont just give me an answer
posledela
There are two methods to solve this problem. One of them is the typical method and the other one is the short-cut. I will explain the shortcut

Short-cut: 
This method is quick and easy, and works with ALL triangles, which is why I suggest you use this. You make proportions. Since the triangles are similar, we can use CPCTC. Thereafter,
\frac{AD}{CE}= \frac{DB}{EB}

Now, you just need to identify the terms, substitute, and solve for the unknown, which would be k. 

\frac{12}{3} = \frac{k+5}{k-7} \\ 12(k-7)=3(k+5) \\ 12k-84=3k+15 \\ 9k=84+15 \\ 9k=99 \\ k=11[/tex]

So we found k, but it is asking for BE. Therefore, plug in the value of k, which is 11, into the expression for BE, which is k-7.

BE=K-7
k=11
BE=11-7
BE=4

Your answer is 4.





5 0
3 years ago
Mark is solving an equation where one side is a quadratic expression and the other side is a linear expr
Brrunno [24]
It is one believe me
8 0
3 years ago
evaluate the line integral ∫cf⋅dr, where f(x,y,z)=5xi−yj+zk and c is given by the vector function r(t)=⟨sint,cost,t⟩, 0≤t≤3π/2.
meriva

We have

\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} \vec f(\vec r(t)) \cdot \dfrac{d\vec r}{dt} \, dt

and

\vec f(\vec r(t)) = 5\sin(t) \, \vec\imath - \cos(t) \, \vec\jmath + t \, \vec k

\vec r(t) = \sin(t)\,\vec\imath + \cos(t)\,\vec\jmath + t\,\vec k \implies \dfrac{d\vec r}{dt} = \cos(t) \, \vec\imath - \sin(t) \, \vec\jmath + \vec k

so the line integral is equilvalent to

\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} (5\sin(t) \cos(t) + \sin(t)\cos(t) + t) \, dt

\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} (6\sin(t) \cos(t) + t) \, dt

\displaystyle \int_C \vec f \cdot d\vec r = \int_0^{\frac{3\pi}2} (3\sin(2t) + t) \, dt

\displaystyle \int_C \vec f \cdot d\vec r = \left(-\frac32 \cos(2t) + \frac12 t^2\right) \bigg_0^{\frac{3\pi}2}

\displaystyle \int_C \vec f \cdot d\vec r = \left(\frac32 + \frac{9\pi^2}8\right) - \left(-\frac32\right) = \boxed{3 + \frac{9\pi^2}8}

7 0
2 years ago
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