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AnnZ [28]
3 years ago
6

A B C D Which is my answer ^

Mathematics
1 answer:
Mkey [24]3 years ago
7 0

Answer:

A

Step-by-step explanation:


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When dropped, a super ball will bounce back to 80% of its peak height,continuing on in this way for each bounce.
Liono4ka [1.6K]

An expression for the height of the nth bounce is 0.80X^N = Height.

<h3><u>Equations</u></h3>

Since when dropped, a super ball will bounce back to 80% of its peak height, continuing on in this way for each bounce, to determine an expression for the height of the nth bounce the following calculation must be performed:

  • X = Initial value
  • 80% = 0.80
  • N = Number of times the ball bounces
  • 0.80X^N = Height

Therefore, an expression for the height of the nth bounce is 0.80X^N = Height.

Learn more about equations in brainly.com/question/2263981

3 0
2 years ago
Α + 4/5 = 3<br> Solve for a to make the proportion true
Natali5045456 [20]
4/15 should be your answer!
5 0
2 years ago
Read 2 more answers
Identify the type of sequence 1/10, 3/20, 5/30, 7/40...
Dafna11 [192]
Arithmetic sequence: must have a constant common difference.
3/20-1/10=(3-2)/20=1/20
5/30-3/20=(10-9)/60=1/60
Difference is not constant, so no.

Geometric sequence: must have a common ratio
30/20 / (1/10) = 15
5/30 / (3/20) = 100/90 = 10/9 
ratio is not constant, so no.

The answer is (c) neither geometric nor arithmetic

4 0
3 years ago
Question 14 of 25
Naily [24]

Answer:

A

Step-by-step explanation:

perpendicular lines are the negative reciprocals of each other, and a pair of these lines intersects at 90 degrees.

5 0
2 years ago
Read 2 more answers
At the movie theatre, child admission is
Dmitriy789 [7]
Child = $5.70
Adult = $9.80

- We can conclude that the amount of adult is double the amount of child tickets bought. (total of $556.60)

For this, you will need to divide the total amount by two and draw a tree chart with each of the numbers to get the seperation of the two. I would find out how many 9.80s or 5.70s go into $56.60 so you'll just have $500

7 0
2 years ago
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