Hello!
log₃(x) + log₃(x - 6) = log₃(7) <=>
<=> log₃(x * (x - 6)) = log₃(7) <=>
<=> log₃(x² - 6x) = log₃(7) <=>
<=> x² - 6x = 7 <=>
<=> x² - 6x - 7 = 0 <=>
<=> x² + x - 7x - 7 = 0 <=>
<=> x * (x + 1) - 7 * (x + 1) = 0 <=>
<=> (x + 1) * (x - 7) = 0 <=>
<=> x + 1 = 0 and x - 7 = 0 <=>
<=> x = -1 and x = 7, x ∈ { 6; +∞ } <=>
<=> x = 7
Good luck! :)
9. negative 10. negative 11. negative 12.negative 13.negative 14. positive 15. positive 16. negative 17. negative 18. positive
Given:
Area = 18
Length = 8
Width = ?
Area = length * width
(Substitute the values)
18 = 6 * width
Width = 18 / 6
Width = 3mm
Therefore, width of the rectangle is 3mm
To check if the answer is correct
Area = length * width
Area = 6 * 3
Area = 18 mm2
Answer:
Quadrant 3
Step-by-step explanation:
Since both x and y are negative they go in the quadrant number 3.
