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pashok25 [27]
3 years ago
14

What newer technology automatically configures cpu multipliers and speeds?

Computers and Technology
1 answer:
andreev551 [17]3 years ago
7 0

Answer

CPUID opcode

Explanation

CPUID opcode is a processor supplementary instruction that allows the software to discover the details of a processor. It configures CPU multipliers and speeds The CPUID opcode is derived from CPU identification

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a network administrator for a large oil company has discovered that a host on the company network has been compromised by an att
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My recommendation as an immediate response to prevent further spoofing of the host is to Revoke the host's certificate.

<h3>What does revoke certificate mean?</h3>

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Learn more about network administrator from

brainly.com/question/4264949

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Which of the following are downlink transport channels?
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write a java program that prompts the user to enter scores (each number an integer from 0 to 10) and prints the following output
Vladimir [108]

Answer:

Explanation:

The following is written in Java. It continues asking the user for inputs until they enter a -1. Then it saves all the values into an array and calculates the number of values entered, the highest, and lowest, and prints all the variables to the screen. The code was tested and the output can be seen in the attached image below.

import java.util.ArrayList;

import java.util.Arrays;

import java.util.Scanner;

class Brainly {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       int count = 0;

       int highest, lowest;

       ArrayList<Integer> myArr = new ArrayList<>();

       while (true) {

           System.out.println("Enter a number [0-10] or -1 to exit");

           int num = in.nextInt();

           if (num != -1) {

               if ((num >= 0) && (num <= 10)) {

                   count+= 1;

                   myArr.add(num);

               } else {

                   System.out.println("Wrong Value");

               }

           } else {

               break;

           }

       }

       if (myArr.size() > 3) {

           highest = myArr.get(0);

           lowest = myArr.get(0);

           for (int x: myArr) {

               if (x > highest) {

                   highest = x;

               }

               if (x < lowest) {

                   lowest = x;

               }

           }

           System.out.println("Number of Elements: " + count);

           System.out.println("Highest: " + highest);

           System.out.println("Lowest : " + lowest);

       } else {

           System.out.println("Number of Elements: " + count);

           System.out.println("No Highest or Lowest Elements");

       }

   }

}

4 0
2 years ago
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