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Nadya [2.5K]
3 years ago
9

The coefficient of xy in the product of (4x2 + 2y) and (3x + y2) is

Mathematics
2 answers:
nadya68 [22]3 years ago
4 0

(4x² + 2y)(3x + y²) =  

12x³ + 4x²y² + 6xy + 2y³

The coefficient of xy is 6

icang [17]3 years ago
3 0
In polynomials, when a term contains both a number and a variable part, the number is called the co-efficient. 
In this problem the co-efficient of x = 
(8+y)+(3x+y2)
3y+3x+8
Therefore the co efficient of x and y is 3


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PLEASE HELP!
emmainna [20.7K]

Use the given recursion and starting value of x_0 = 2.4 to find x_1 :

x_1 = \dfrac{x_0 + \frac6{x_0}}2 = \dfrac{2.4 + \frac{6}{2.4}}2 = 2.45

Do the same for x_2 and x_3 :

x_2 = \dfrac{x_1 + \frac6{x_1}}2 = \dfrac{2.45 + \frac6{2.45}}2 \approx 2.44949

x_3 = \dfrac{x_2+\frac6{x_2}}2 \approx \dfrac{2.44949 + \frac6{2.44949}}2 \approx \boxed{2.44949}

(That's not a mistake. This just tells you that the 2nd and 3rd iterates are very close together and have at least the same first 5 digits after the decimal.)

5 0
2 years ago
Please help me!!!! brainliest
dimaraw [331]

Answer:

2/5in x 3/5in

=

(3 x 2) + (5 x 5)

=

6/25

8 0
3 years ago
Read 2 more answers
Find the length of the picture frame whose width is 3 inches and whose proportions are the same as 9- inches by 12-inch long fra
andrew11 [14]

Answer:

9-

Step-by-step explanation: 9-

4 0
3 years ago
If a ball rotates 110 degrees in 8 seconds, how many degrees does it rotate in 32 seconds?
Vlad1618 [11]
Well 32 divided by 8 would be 4 so... 32 x 4 would be 128 so 128 times. If it’s not correct I’m really sorry.
6 0
4 years ago
Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.
lesya [120]

Answer:

0.1994 is the required probability.      

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

Standard error due to sampling =

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851

P(sample of 20 boxers is more than 167 pounds)

P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)

= 1 - P(z \leq 0.8438)

Calculation the value from standard normal z table, we have,  

P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

3 0
3 years ago
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