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LenaWriter [7]
3 years ago
6

Logic You find that the product of 93 and 6 is 558. He can you use addition to check your answer ? How can you use division yo c

heck answer?
Mathematics
1 answer:
frozen [14]3 years ago
3 0
Addition: 93 can be added six times to determine the total

and division can be used to check your answer since it's the inverse operation of multiplication...take your solution of 558 and divide it by 6 (or 93) to see if 93 times six equals 558
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Please help!!!! I will mark brainlest
ipn [44]
I think it’s (-3, -1)
8 0
3 years ago
What is 2log5(5x^3)+(1/3)log5((x^2)+6) written as a single logarithm?
joja [24]
Assuming 5 is the base. I'm going to leave that out for now.

2log(5x^3) + (1/3)log(x^2+6)

power rule
log(5^2 x^3*2) + log((x^2 + 6)^(1/3))

log(25x^6) + log((x^2 + 6)^(1/3))

quotient rule
log(25x^6 / (x^2 + 6)^(1/3))
4 0
3 years ago
Read 2 more answers
What values of a and b would make the equation shown have infinitely many solutions? 3x=ax+b
Wittaler [7]
Infinitely many solutions means that you have the same thing on both sides of the equation no matter what value of x you plug in, right?

We just need both sides to be 3x then, correct?

If a were equal to 3 and b were equal to 0, we'd have

3x = (3)x + 0

Which is essentially 3x = 3x

So that means a = 3 and b = 0 must work!
Let's say x = 5

3(5) = 3(5) + 0

15 = 15 + 0

15 = 15

That means that a = 3 and b = 0 is your final answer :)
7 0
3 years ago
| 357,25235 divided by 7252 ​
Dmitriy789 [7]

4926.25965251

I used a calculator because it makes solving this much easier

3 0
3 years ago
Pls, help me I don't understand! Very urgent!!!! (I have an attachment so you know what the problem looks like)
vredina [299]

1. A pair of supplementary angles: ∠IJH and ∠HJG, ∠IJH and ∠HJG

2. A pair of complementary angles: ∠JGK and ∠KGC, ∠FGE and ∠EGD

3. A pair of vertical angles: ∠AKB and ∠KJG , ∠IJH and ∠KJG

Solution:

<em>Two angles are said to be supplementary when they add up to 180°.</em>

We know that,

Sum of the adjacent angles in a straight line = 180°

∠IJK + ∠KJG = 180°

Therefore ∠IJK and ∠KJG are supplementary angles.

∠IJH + ∠HJG = 180°

Therefore ∠IJH and ∠HJG are supplementary angles.

<em>Two angles are said to be complementary when they add up to 90°.</em>

Given ∠CGD = 90°, ∠CGJ = 90°

∠JGK + ∠KGC = ∠CGJ

∠JGK + ∠KGC = 90°

Therefore ∠JGK and ∠KGC are complementary angles.

∠FGE + ∠EGD = 90°

Therefore ∠FGE and ∠EGD are complementary angles.

<em>If two lines are intersecting, then the angles opposite to vertical point are vertical angles and they are equal.</em>

∠AKB = ∠KJG (vertically opposite)

∠IJH = ∠KJG (vertically opposite)

5 0
4 years ago
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