<h3><em>Answer </em><em>:</em></h3>
- A rhombus has side lengths of 25. What could be the lengths of the diagonals? From 0 to (25+25) = 50 units, exclusive.
# XxQueenJiAexX
<span>
<u><em>The correct answer is: </em></u>green and blue.
<u><em>Explanation</em></u><span>
<u><em>: </em></u>We want to see which fractions </span></span>
![\frac{3}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B4%7D%20)
is a multiple of. We know that
![\frac{3}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B4%7D%20)
is a multiple of
![\frac{1}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B4%7D%20)
, because
![\frac{1}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B4%7D%20)
*3=
![\frac{3}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B4%7D%20)
.
We can divide fractions to determine if
![\frac{3}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B4%7D%20)
is a multiple of
![\frac{1}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20)
:
![\frac{ \frac{3}{4}}{ \frac{1}{2}}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%5Cfrac%7B3%7D%7B4%7D%7D%7B%20%5Cfrac%7B1%7D%7B2%7D%7D%20)
;
in order to divide fractions, flip the second one and multiply:
![\frac{3}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B4%7D%20)
)*
![\frac{2}{1}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%7D%7B1%7D%20)
=
![\frac{6}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B6%7D%7B4%7D%20)
=1
![\frac{1}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20)
.
This did not divide evenly, so
![\frac{3}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B4%7D%20)
is not a multiple of 1/2.
Checking to see if
![\frac{3}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B4%7D%20)
is a multiple of
![\frac{1}{8}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B8%7D%20)
,
![\frac{ \frac{3}{4}}{ \frac{1}{8}}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%5Cfrac%7B3%7D%7B4%7D%7D%7B%20%5Cfrac%7B1%7D%7B8%7D%7D%20)
;
flip the second one and multiply:
![\frac{3}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B4%7D%20)
*
![\frac{8}{1}](https://tex.z-dn.net/?f=%20%5Cfrac%7B8%7D%7B1%7D%20)
=
![\frac{24}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B24%7D%7B4%7D%20)
=6.
This divided evenly, so
![\frac{3}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B4%7D%20)
is a multiple of
![\frac{1}{8}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B8%7D%20)
.
All you have to do is to solve this problem is 60+2+0.20+0.02