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3 years ago

Easy question for easy points

Mathematics

2 answers:

poizon [28]3 years ago

5 0

Answer:

50 berries left over

Step-by-step explanation:

55 berries 1700 berries

--------------- = -------------------

1 jar x jars

Using cross products

55x = 1700*1

Divide each side by 55

55x/55 = 1700/55

x = 1700/55

Changing to a mixed number

55 goes into 1700 30 times

30 *55 =16501700-1650 = 50

x = 30 50/55 = 30 10/11

There are 50 berries left over

saveliy_v [14]3 years ago

4 0

Answer:

50 berries left over

Step-by-step explanation:

55 berries 1700 berries

--------------- = -------------------

1 jar x jars

Using cross products

55x = 1700*1

Divide each side by 55

55x/55 = 1700/55

x = 1700/55

Changing to a mixed number

55 goes into 1700 30 times

30 *55 =16501700-1650 = 50

x = 30 50/55 = 30 10/11

There are 50 berries left over

Step-by-step explanation:

You might be interested in

Ryan can text 22 words in 4 minutes. At this rate, how many words could he text in 12 minutes? Fill out the table of equivalent

aleksandrvk [35]

The answer would be 66
Explanation: first you have to divide the minutes so 12 divided by 4 equals 3 so you would take the three and multiply that by 22. So 22x3 is equal to 66

3 0

3 years ago

The arch beneath a bridge is semi-elliptical, a one-way roadway passes under the arch. The width of the roadway is 38 feet and

forsale [732]

Answer:

Only truck 1 can pass under the bridge.

Step-by-step explanation:

So, first of all, we must do a drawing of what the situation looks like (see attached picture).

Next, we can take the general equation of an ellipse that is centered at the origin, which is the following:

$\frac{x^2}{a^2}+\frac{y^2}{b^2}$

where:

a= wider side of the ellipse

b= shorter side of the ellipse

in this case:

$a=\frac{38}{2}=19ft$

and

b=12ft

so we can go ahead and plug this data into the ellipse formula:

$\frac{x^2}{(19)^2}+\frac{y^2}{(12)^2}$

and we can simplify the equation, so we get:

$\frac{x^2}{361}+\frac{y^2}{144}$

So, we need to know if either truk will pass under the bridge, so we will match the center of the bridge with the center of each truck and see if the height of the bridge is enough for either to pass.

in order to do this let's solve the equation for y:

$\frac{y^{2}}{144}=1-\frac{x^{2}}{361}$

$y^{2}=144(1-\frac{x^{2}}{361})$

we can add everything inside parenthesis so we get:

$y^{2}=144(\frac{361-x^{2}}{361})$

and take the square root on both sides, so we get:

$y=\sqrt{144(\frac{361-x^{2}}{361})}$

and we can simplify this so we get:

$y=\frac{12}{19}\sqrt{361-x^{2}}$

and now we can evaluate this equation for x=4 (half the width of the trucks) so:

$y=\frac{12}{19}\sqrt{361-(8)^{2}}$

y=11.73ft

this means that for the trucks to pass under the bridge they must have a maximum height of 11.73ft, therefore only truck 1 is able to pass under the bridge since truck 2 is too high.