Answer:
la aplicacion me gusta mucho la verdad
Check the picture below.
so the shape is really 4 triangles with a base of 2 and a height of 4 each, and 2 squares tha are 4x4.
![\bf \stackrel{\textit{area of the 4 triangles}}{4\left[\cfrac{1}{2}(2)(4) \right]}~~+~~\stackrel{\textit{area of the two squares}}{2(4\cdot 4)}\implies 16+32\implies 48](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%204%20triangles%7D%7D%7B4%5Cleft%5B%5Ccfrac%7B1%7D%7B2%7D%282%29%284%29%20%5Cright%5D%7D~~%2B~~%5Cstackrel%7B%5Ctextit%7Barea%20of%20the%20two%20squares%7D%7D%7B2%284%5Ccdot%204%29%7D%5Cimplies%2016%2B32%5Cimplies%2048)
Use Pythagorean Theorem of a^2 + b^2 = c^2 where a and b are the legs of the triangle set up by the house height and the ground, and c is the hypotenuse or how long the ladder is. C is going to be our unknown.
Just plugging in you get 25^2 + 35^2 = c^2. Simplify to 625 + 1225 = c^2. Simplify again to 1850 = c^2. The square root both sides to isolate the variable c. C = sqrt(1850) or approximately 43.0116 feet if rounded to 4 decimal places.
The ladder is approximately 43.0116 feet long.
