Answer:
Check the explanation
Explanation:
#include <iostream>
using namespace std;
void hex2dec(string hex_num){
int n = 0;
//Loop through all characters in string
for(int i=0;i<hex_num.size();i++){
//take ith character
char c = hex_num[i];
//Check if c is digit
if(c>='0' && c<='9'){
n = 16*n + (c-48);
}
//Convert c to decimal
else{
n = 16*n + (c-55);
}
}
cout<<hex_num<<" : "<<n<<endl;
}
int main()
{
hex2dec("EF10");
hex2dec("AA");
return 0;
}
The Output can be seen below :
Answer:
The answer is "Option A".
Explanation:
- In the given C++ Language program on line 8 compile-time error will occur, because in the code the conditional statement is used. In if block, we check two conditions together, which is the number variable value is greater than equal to 0 and check less than equal to 100.
- In this condition statement, a AND operator is used that execute when both condition is true, but in the last condition, we do not define a variable name that, checks value. That's why the program will give an error on line 8.
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Answer D isn't a successful budgeting strategy.