Answer:
carbon dioxide, hydrogen, and water
salt, urea, and water
urine, alcohol, and water
fats, ammonia, and water
Answer:
The thin external covering is similar to the Cell Membrane. The organelle with a texture like sandpaper is the rough endoplasmic reticulum (ER)
In case of the genes that assort independently in a test cross, the phenotypic ratio is 1: 1: 1: 1. In the given case, the total number of phenotypes is 400, thus, every phenotype should be 100 each. Since that is not the case, it may be concluded that the genes are not assorting independently.
Thus, to determine the chi-square = (observed-expected)^2 / expected.
By putting the values, we get the values of chi-square as
AB = 4.84
Ab = 3.24
aB = 3.61
ab = 4.41
Thus, the chi-square value will be the addition of the individual values that comes out to be 16.1. Here there are three degrees of freedom (Number of classes-1). Observing at the P table, this puts the value of P < 0.005.
A large chi-square value suggests that independent assortment actually did not occur as the expected and the observed values were very distinct.
Parallel circuits are circuits when placed in a parallel
position. Meaning that for each device, they have their own branch. The voltage
that is received in the circuit is equal to the individual devices. The total
current is equal to the current of each device. The resistance is the reciprocal
of the resistances of each device combined.
Given:
Device 1 = 12 ohms
Device 2 = 4 ohms
Voltage total = 40V
Required:
Current at 12 ohms
Solution:
40V = V1 =V2
Since V =IR
I1 = V1/R1
I1 = (40V)/(12 ohms)
<span><u>I1 = 3.334 A(Amperes)</u></span>