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3 years ago

Solve Please:(c^5)(c)(c^2) Thank You ^-^

Mathematics

1 answer:

soldier1979 [14.2K]3 years ago

7 0

Answer:

c^(8)

Step-by-step explanation:

(c^5)(c)(c^2)

When the bases are the same, we can add the exponents when multiplying

The implied exponent on c is c^1

c^( 5+1+2)

c^(8)

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How do I go about solving (27x^3/8y^9)^5/3? And what is the role of the numerator and denominator?

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Now, If the exponent was negative like you asked....

$\left( \frac{27x^3}{8y^9}\right)^ {-\frac{5}{3}} \\\\\\ =\left( \frac{8y^9}{27x^3}\right)^ {\frac{5}{3}}\\\\\\ =\left( \frac{(2y^3)^3}{(3x)^3}\right)^ \frac{5}{3} \\\\\\ = \frac{(2y^3)^{3 \times \frac{5}{3} }}{(3x)^{3 \times \frac{5}{3} }} \\\\\\ =\frac{(2y^3)^{5 }}{(3x)^5} \\\\\\ =\frac{32y^{15}}{243x^5}$

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