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erma4kov [3.2K]
3 years ago
9

Solve for x. Write the smaller solution first, and the larger solution second. 2x^2-5=13

Mathematics
2 answers:
lianna [129]3 years ago
8 0

Answer:

x= -3

Step-by-step explanation:

mark branliest pls

Standard form:

2x2 − 18 = 0

Factorization:

2(x + 3)(x − 3) = 0

Solutions based on factorization:

x + 3 = 0   ⇒   x1 = −3

x − 3 = 0   ⇒   x2 = 3

Extrema:

Min = (0, −18)

Savatey [412]3 years ago
4 0

Answer:

x = ± 3

Step-by-step explanation:

Given

2x² - 5 = 13 ( add 5 to both sides )

2x² = 18 ( divide both sides by 2 )

x² = 9 ( take the square root of both sides )

x = ± \sqrt{9} = ± 3

smaller solution is x = - 3

larger solution is x = 3

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Which expression is equivalent?
babymother [125]

Answer:

Third choice from the top is the one you want

Step-by-step explanation:

This whole concept relies on the fact that if the index of a radical exactly matches the power under the radical, both the radical and the power cancel each other out.  For example:

\sqrt[6]{x^6} =x and another example:

\sqrt[12]{2^{12}}=2

Let's take this step by step.  First we will rewrite both the numerator and the denominator in rational exponential equivalencies:

\frac{\sqrt[4]{6} }{\sqrt[3]{2} }=\frac{6^{\frac{1}{4} }}{2^{\frac{1}{3} }}

In order to do anything with this, we need to make the index (ie. the denominators of each of those rational exponents) the same number.  The LCM of 3 and 4 is 12.  So we rewrite as

\frac{6^{\frac{3}{12} }}{2^{\frac{4}{12} }}

Now we will put it back into radical form so we can rationalize the denominator:

\frac{\sqrt[12]{6^3} }{\sqrt[12]{2^4} }

In order to rationalize the denominator, we need the power on the 2 to be a 12.  Right now it's a 4, so we are "missing" 8.  The rule for multiplying like bases is that you add the exponents.  Therefore,

2^4*2^8=2^{12}

We will rationalize by multiplying in a unit multiplier equal to 1 in the form of

\frac{\sqrt[12]{2^8} }{\sqrt[12]{2^8} }

That looks like this:

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This simplifies down to

\frac{\sqrt[12]{216*256} }{\sqrt[12]{2^{12}} }

Since the index and the power on the 2 are both 12, they cancel each other out leaving us with just a 2!  Doing the multiplication of those 2 numbers in the numerator gives us, as a final answer:

\frac{\sqrt[12]{55296} }{2}

Phew!!!

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4 years ago
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2 years ago
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marishachu [46]

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* = times

I hope this helps! :)

5 0
3 years ago
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