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Leni [432]
3 years ago
13

Please help!! determine an equation ( ax^3 * bx^2 + cx + d ) for the data.

Mathematics
1 answer:
Aliun [14]3 years ago
5 0

Answer:

abx^5+cx+d

Step-by-step explanation:

This is the expression simplified

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Hope this helps but I think the answer is $8.91.

4 0
3 years ago
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Joe is building a fort for his little brother out of boxes. He is wondering how much room there will be inside the fort.
ser-zykov [4K]

Answer:

Depends on how wide and tall it is

Step-by-step explanation:

5 0
2 years ago
Solve the equation
kondor19780726 [428]

4 1/5 + B = 9 3/5

21/5 + B = 48/5

B = 27/5

B = 5 2/5

Letter C is the correct answer!

Hope this helps! ;)

4 0
4 years ago
​Find all roots: x^3 + 7x^2 + 12x = 0 <br> Show all work and check your answer.
Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

<u>Solution:</u>

We have been given a cubic polynomial.

x^{3}+7 x^{2}+12 x=0

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

x^{3}+7 x^{2}+12 x=0

x\left(x^{2}+7 x+12\right)=0   ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

x^{2}+7 x+12=0

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}

<em><u>Therefore, the two roots are:</u></em>

\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}

And,

\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0
3 years ago
The height of Josie's dog is 11 1/4 inches to the nearest quarter inch and 11 inches to the nearest half inch. Which measurement
goldenfox [79]
Dear Kellyeasterday, 11 1/4 inches is more precise.
5 0
3 years ago
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