3 years ago

Please help!! determine an equation ( ax^3 * bx^2 + cx + d ) for the data.

Mathematics

1 answer:

Aliun [14]3 years ago

5 0

Answer:

abx^5+cx+d

Step-by-step explanation:

This is the expression simplified

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2 years ago

Mackenzie spent a total of $17.50 on Saturday afternoon.She bought a movie ticket for $7.25 and snacks for $4.95.She spent the r

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17.50-7.25-4.95=5.30/2=2.65

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2 years ago

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Paul [167]

The distance between two points on the plane is given by the formula below

$\begin{gathered} A=(x_1,y_1),B=(x_2,y_2) \\ \Rightarrow d(A,B)=\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2} \end{gathered}$

Therefore, in our case,

$A=(-1,-3),B=(5,2)$

Thus,

$\begin{gathered} \Rightarrow d(A,B)=\sqrt[]{(-1-5)^2+(-3-2)^2}=\sqrt[]{6^2+5^2}=\sqrt[]{36+25}=\sqrt[]{61} \\ \Rightarrow d(A,B)=\sqrt[]{61} \end{gathered}$

Therefore, the answer is sqrt(61)

In general,

$-(-n)=n$

Remember that

$-n=(-1)\cdot n$

Therefore,

$\begin{gathered} a-(-n)=a+(-1)(-n)=a+(-1)(-1\cdot n)=a+(-1)^2\cdot n=a+1\cdot n=a+n \\ \Rightarrow a-(-n)=a+n \end{gathered}$

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1 year ago

Input Output

Jet001 [13]

C.25 because 11-6 is five 13-8 is five and 15-10 is five so 25-20 is five

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3 years ago