Answer:
5494
Step-by-step explanation:
Assuming all members of each set registered, the total number is ...
2(2697) +3(29) +4(2) +5(1) = 5494
__
Since you're concerned with order of operations, perhaps you want to see the working out.
= 5394 + 87 +8 +5 . . . . perform all the multiplications
= 5481 +8 +5 . . . . . . . . . perform addition left to right
= 5489 +5
= 5494
Using the chain rule: The derivative of e^u is (e^u)(u'). Notice that e^u is rewritten exactly as is and then multiplied by the derivative of the exponent.
Let u=2x. So u'=2
So the derivative of e^u is e^(2x)*2 This can also be written as 2e^(2x).
Answer: d. None of the above are correct.
Step-by-step explanation: Noise is a superfluous random alteration in an eletrical signal. There are different types of noises created by different devices and process. Thermal noise is one of them. It is unavoidable because is created by the agitation of the charge carriers, due to temperature, inside an eletrical conductor at equilibrium and is present in all eletrical circuits.
The formula to find the thermal noise power (N) is: N =
.T.B, where:
is Boltzmann constant (1.38.
J/K);
T is temperature in Kelvin;
B is the bandwith;
Calculating the thermal noise power:
N = 1.38.
·292·40
N = 16118.4.
dBm
The thermal noise power [N] = 16118.4.
dBm
Noise power density or simply Noise density (N₀) is the noise power per unit of bandwith and its SI is watts per hertz.
For thermal noise, N₀ = kT, where
<em>k </em>is the Boltzmann constant in J/K;
T is the receiver system noise temperature in K;
N₀ = 1.38.
. 292
N₀ = 402.96.
W/Hz
The thermal noise power density [N₀] = 402.96.
W/Hz
Answer:
c
Step-by-step explanation: