Given:
cos 120°
To find:
The exact value of cos 120° in simplest form with a rational denominator.
Solution:
We have,
It can be written as
![[\because \cos (90^\circ-\theta)=-\sin \theta]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Ccos%20%2890%5E%5Ccirc-%5Ctheta%29%3D-%5Csin%20%5Ctheta%5D)
![[\because \sin 30^\circ=\dfrac{1}{2}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Csin%2030%5E%5Ccirc%3D%5Cdfrac%7B1%7D%7B2%7D%5D)
Therefore, the exact value of cos 120° is 
.
Answer:
m∠N = 32°
NQ = 106°
When finding inscribed angles like ∠N with the intercepted arc, the equation is ∠N=1/2MP. (Inscribed angles are always half the degree of the arc length.) Plug in the corresponding value to get ∠N=1/2(64) to get 32°. When finding the angle of the intercepted arc with inscribed angles like NQ, the equation is NQ=2(∠P). Plug in the corresponding value to get 2(53) to get 106°.
Answer:
(12)(3)(-2)
Step-by-step explanation:
Answer:
h(x) = x³ + 4x² - 49x - 196
Step-by-step explanation:
h(x) = (x² - 49)(x + 4) <== distribute
h(x) = x²(x) - 49(x) + x²(4) - 49(4)
h(x) = x³ - 49x + 4x² - 196 <== rewrite in standard form (descending degrees)
h(x) = x³ + 4x² - 49x - 196
Hope this helps!
