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lana [24]
3 years ago
10

Which are acceptable reasons for studying history? Choose all answers that are correct.

Mathematics
1 answer:
zimovet [89]3 years ago
5 0
I think A and B are the correct answers
You might be interested in
Given the function h(t)=2f^2+9 evaluate h(5)
Schach [20]

Answer:

Concept: Evaluating Functions

  1. h(5) is equivalently h(t)
  2. Hence 2(5)^2+9
  3. So the answer is 59
4 0
3 years ago
Read 2 more answers
In △ABC, m∠A=45°, c=17, and m∠B=25°. Find a to the nearest tenth. law of sines 4
rjkz [21]

Answer:

12.8

Step-by-Step Explanation:

In triangle ABC, m<A=45, c=17, and m<B=25.

so m<C = 180-(45+25)=180-70=110

using law of sin

sin A/ a = sin C/c

sin 45/ a = sin 110 / 17

sin 45/ (sin 110/17) = a

0.707 / 0.055 = a

12.79 =a

12.8 =a

so answer is 12.8

4 0
3 years ago
Marty lives 2/3 mile from school. Linda lives 3/4 as far from school as Marty does. how far does Linda live from school?
Arturiano [62]
A half mile
\frac{2}{3}•\frac{3}{4}=\frac{6}{12}
Which simplifies to \frac{1}{2}
Hope that helps
7 0
3 years ago
A system of equations is shown:
nikklg [1K]

Answer:

2

Step-by-step explanation:

x + 3y = 5 (equation 1)

2+3=5

7x − 8y = 6 (equation 2)

5 0
3 years ago
Dont answer if u dont know the answer pls
mote1985 [20]

Answer:

The answer is:

\left[\begin{array}{ccc}-29&-16\\14&15\end{array}\right]

Step-by-step explanation:

(Presuming you wanted to add these)

From the image that is given/shown, this is matrices.

In matrices, the numbers will somewhat correlate with each other!

From what is stated, "Find 3M + 7N"

We must substitute in M and N for the pair of matrices that are given:

M = \left[\begin{array}{ccc}2&-3\\0&6\\\end{array}\right]  and N = \left[\begin{array}{ccc}-5&-1\\2&9\\\end{array}\right]

You will then be left with:

3\left[\begin{array}{ccc}2&-3\\0&6\\\end{array}\right]  + 7\left[\begin{array}{ccc}-5&-1\\2&9\\\end{array}\right]

when then need to add these together:

1) First Multiply the matrix by 3, you'll get:

\left[\begin{array}{ccc}6&-9\\0&18\\\end{array}\right] + 7\left[\begin{array}{ccc}-5&-1\\2&9\\\end{array}\right]

(Each number in the matrix is being multiplied by the values: 3 or 7)

2) Then Multiply the matrix by 7, and you'll get:

\left[\begin{array}{ccc}6&-9\\0&18\\\end{array}\right] + \left[\begin{array}{ccc}-35&-7\\14&63\\\end{array}\right]

3) Add the matrices:

\left[\begin{array}{ccc}6+(-35)&-9+(-7)\\0+(14)&18+(63)\\\end{array}\right]

6 - 35 = -29

-9 - 7 = -16

0 + 14 = 14

18 + 63 = 81

After solving the matrices, you get:

\left[\begin{array}{ccc}-29&-16\\14&15\end{array}\right]

7 0
4 years ago
Read 2 more answers
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