We know that , in a circle radius perpendicular to chord will bisect the chord.
OM=18, so OQ=QM=18/2=9.
Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
Answer:
4x + 1
Step-by-step explanation:
Multiply f + g by x because f + g is in parenthesis:
f(x) + g(x)
Then implement equation #1 for f(x) into our equation:
3x - 1 + g(x)
Then implement the other equation for g(x) into our equation:
3x - 1 + x + 2
Then switch the positions of -1 and +x:
3x + x - 1 + 2
Simmplify:
4x + 1
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Answer: 3/1000 as a decimal is 0.003.
Explanation;
3/10 = 0.3
0.3/10 = 0.03
0.03/10 = 0.003
Answer:
f=13/9
Step-by-step explanation:
f-8/9=5/9
solution
f=5/9+8/9
f= 5+8/9=13/9
9514 1404 393
Answer:
83 m
Step-by-step explanation:
The attached diagram shows the lengths of the midlines to be 3.16 and 5.10 units on the coordinate plane. The sum of these is (3.16 +5.10) = 8.26 coordinate plane units. Since each unit on the coordinate plane represents 10 m, the total path length is about ...
8.26(10 m) = 82.6 m ≈ 83 m
_____
The distance formula will tell you the distances are ...
AC = √(3² +1²) = √10
BD = √(5² +1²) = √26
The total path length is about (10 m)(√10 +√26) ≈ 82.61230 m ≈ 83 m.