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Sever21 [200]
4 years ago
8

Can someone helpppp me on this question!! Asap thank! ​

Mathematics
1 answer:
eimsori [14]4 years ago
8 0

Answer:

The answer it's the c

Step-by-step explanation:

1 Trillion it's 1.000.000.000.000

4 * 10^13 it's 40.000.000.000.000

2 * 10^7 it's 20.000.000

2 * 10^7 * 2 * 10^7 it's 4 * 10^14

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In a building there are 14 pillars. The radius of each pillar is 21 cm and height 3.5 m. Find the cost
tester [92]

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I don't know well I didn't got the answer sorry I tried my best

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kobusy [5.1K]
Xintercept is where the line crosses the x axis or where y=0
yintercept is where the line crosses the y axis or where x=0
aka
finding the finding the x intercept is finding the x value when y=0
finding the finding the y intercept is finding the y value when x=0

y=-1/2x-5
xint
y=0
0=-1/2x-5
5=-1/2x
-10=x
(-10,0) is x intercpet

yint
set x=0
y=-1/2(0)=5
y=-5
(0,-5) is yint



xint: x=-10 or at point (-10,0)
yint: y=-5, or at point (0,-5)
8 0
3 years ago
What is the input to a trigonometric function? A ratio, the x position of a point of the circle, a central angle of a circle or
devlian [24]

Answer:

hat is the input to a trigonometric function? A ratio, the x position of a point of the circle, a central angle of a circle or the y position of a point on the circle

Ask for details FollowReport by Sevanah9445 3 days ago

Answers

Step-by-step explanation:

8 0
3 years ago
Which statement explains how to correct the error that was made?
Svetradugi [14.3K]

Answer:

I believe that this is the best answer mark brainliest if it is

Step-by-step explanation:

The square root property should have been applied to both complete sides of the equation instead of to select

variables.

4 0
3 years ago
Let S(x, y) denote the statement "x has seen y" and D denote the set of all students in our class and M be the set of all movies
oksano4ka [1.4K]

Answer:

Step-by-step explanation:

a) Recall the quantifiers \forall, \exists.

Then, we can translate the proposition as follows

\forall m \in M \exists x \in D \exists y \in D S(x,m)\land S(y,m)

b) Recall that an expression of the form \exists x P(x) its negation is of the form \forall x \neg P(x) which means that it is not true that for all elements the proposition P holds. Equivalently, we have that the negation of an expression of the form \forall x P(x) is \exists x \neg P(x) which means that there is at least one x such that P doesn't hold. Using this, we get the following

\neg(\forall m \in M \exists x \in D \exists y \in D S(x,m)\land S(y,m))= \exists m \in M \neg (\exists x \in D \exists y \in D S(x,m)\land S(y,m))= \exists m \in M \forall x \in D \neg (\exists y \in D S(x,m)\land S(y,m))= \exists m \in M \forall x \in D \forall y \in D \neg(S(x,m)\land S(y,m))

By De Morgan's law, we have that \neg (A \land B) = \neg A \lor \neg B

So, the final statement is

\exists m \in M \forall x \in D \forall y \in D \neg S(x,m) \lor \neg S(y,m)

c)

This statement means: There is a movie that for every pair of students, at least one of the students hasn't seen the movie yet.

8 0
3 years ago
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