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katen-ka-za [31]

3 years ago

10

Please help quickly.

1 answer:

Thepotemich [5.8K]3 years ago

3 0

$\bf slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ h(t_2)}}-{{ h(t_1)}}}{{{ t_2}}-{{ t_1}}}\impliedby 
\begin{array}{llll}
average\ rate\\
of\ change
\end{array}
\\\\\\
h(t)=300-16t^2\quad 
\begin{cases}
t_1=0\\
t_2=3
\end{cases}\implies \cfrac{h(3)-h(0)}{3-0}\implies \cfrac{h(3)-h(0)}{3}$

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