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Licemer1 [7]
3 years ago
13

Determine the length of the hypotenuse in a right triangle with legs 5 inches and 12 inches

Mathematics
1 answer:
Alborosie3 years ago
7 0

In a right angled triangle we can use Pythagoras theorem to determine third side in case two sides are given.

The formula of Pythagoras theorem is given by:

x^{2} +y^{2} =z^{2}

Where x , y and z are sides of triangle , z is hypotenuse.

Now we use this formula to find hypotenuse.

Plugging other two sides which are 5 in. and 12 in.

5^{2} +12^{2} =z^{2}

25 +144 =z^{2}

169 =z^{2}

Taking square root on both sides

square root of 169 is 13

so we have z=13

Hypotenuse is 13 inches.


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Find the Derivative y’ implicitly.
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katen-ka-za [31]

Answer:

44.47 cm² (nearest hundredth)

Step-by-step explanation:

Area of ΔABC = 1/2 x base x height

⇒ 21 = 1/2 x 7 x BC

⇒ BC = 6 cm

Pythagoras' Theorem: a² + b² = c²

(where a and b are the legs, and c is the hypotenuse, of a right triangle)

⇒ AB² + BC² = AC²

⇒ 7² + 6² = AC²

⇒ AC² = 85

⇒ AC = √85 cm

Cosine rule to find length AD:

      c² = a² + b² - 2 ab cosC

⇒ DC² = AD² + AC² - 2(AD)(AC)cos(DAC)

⇒ 9.2² = AD² + (√85)² - 2(AD)(√85)cos 73°

⇒ AD²  - 5.39106...AD + 0.36 = 0

⇒ AD = 5.323442445, 0.06762541414

⇒ AD = 5.323442445

Area of a triangle ADC: (1/2)absinC

(where a and b are adjacent sides and C is the angle between them)

⇒ area = (1/2) × AC × AD × sin(DAC)

⇒ area = (1/2) × √85 × 5.323442445 × sin(73°)

⇒ area =23.4675821... cm²

Area of quadrilateral = area of ΔABC + area of ΔADC

                                   = 21 + 23.4675821...

                                   = 44.47 cm² (nearest hundredth)

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2 years ago
Find the slope of the line.
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The slope is 2 because after u use the slope formula u get 4/2 which reduces to 2
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3 years ago
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