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3 years ago

Use the difference of squares pattern to factor the polynomial.x2 − 16y2 how would I do this

1 answer:

6 0

The general rule for difference of two squares is that when factorised it can be written in the form (a+b)(a-b) where a is the square root of the first part of the function and b is the square root of the second part of the function.
From this we can find the square root of x² to find a and the square root of 16y² to find b.
In this case √x²=x and √16y²=4y
Therefore fully factorised it can be written as (x+4y)(x-4y)

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valentinak56 [21]

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3 years ago

Solve 3x to the <br> second power <br> -2x-8=0 using an algebraic method

MatroZZZ [7]

Answer:

$x=2\textrm{ or } x=-\frac{4}{3}$

Step-by-step explanation:

Given:

The equation is given as:

$3x^{2}-2x-8=0\\3x^{2}-6x+4x-8=0\\3x(x-2)+4(x-2)=0\\(x-2)(3x+4)=0\\\\x-2=0\textrm{ or }3x+4=0\\x-2+2=0+2 \textrm{ or }3x+4-4=0-4\\x=2\textrm{ or }3x=-4\\x=2\textrm{ or}\\x=-\frac{4}{3}$

Therefore, the possible values of $x$ are 2 and $-\frac{4}{3}$

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3 years ago

In triangle ABC, cos A =

nikitadnepr [17]

The other expression that has a value of $\frac{7}{25}$ is A) sin B.

Step-by-step explanation:

Step 1:

$sin\theta = \frac{oppositeside}{hypotenuse} ,$ $cos\theta = \frac{adjacentside}{hypotenuse} ,$ $tan \theta = \frac{opposite side}{adjacent side} .$

For angle B, the opposite side measures 7 units, the adjacent side measures 24 units and the hypotenuse measures 25 units.

$sinB= \frac{oppositeside}{hypotenuse} = \frac{7}{25} ,$ $tan B = \frac{opposite side}{adjacent side} = \frac{7}{24} ,$ $cosB = \frac{adjacentside}{hypotenuse} = \frac{24}{25}.$

Step 2:

For angle A, the opposite side measures 24 units, the adjacent side measures 7 units and the hypotenuse measures 25 units.

$tan A = \frac{opposite side}{adjacent side} = \frac{24}{25} .$

Step 3:

tan C cannot be determined as C is the right angle. The opposite side and hypotenuse of the triangle would be the same.

So sin B also has a value of $\frac{7}{25}.$ This is option A.

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3 years ago