<h2><u>Part A:</u></h2>
Let's denote no of seats in first row with r1 , second row with r2.....and so on.
r1=5
Since next row will have 10 additional row each time when we move to next row,
So,
r2=5+10=15
r3=15+10=25
<u>Using the terms r1,r2 and r3 , we can find explicit formula</u>
r1=5=5+0=5+0×10=5+(1-1)×10
r2=15=5+10=5+(2-1)×10
r3=25=5+20=5+(3-1)×10
<u>So for nth row,</u>
rn=5+(n-1)×10
Since 5=r1 and 10=common difference (d)
rn=r1+(n-1)d
Since 'a' is a convention term for 1st term,
<h3>
<u>⇒</u><u>rn=a+(n-1)d</u></h3>
which is an explicit formula to find no of seats in any given row.
<h2><u>Part B:</u></h2>
Using above explicit formula, we can calculate no of seats in 7th row,
r7=5+(7-1)×10
r7=5+(7-1)×10 =5+6×10
r7=5+(7-1)×10 =5+6×10 =65
which is the no of seats in 7th row.
The answer is high variability
Make a word problem... I think.
Janie needs to knit 5 shirts. Maddy needs to make 12.5 shirts.They need to do this every day for 9.5 days. How many shirts in total (Maddy and Janie combined) do they make by the end of the 9.5 days?
Answer:
9.5 x (8 + 12.5)
9.5 x 20.5194.75 shirts in total
Did that help?
6 + (10 x 2) = 26 = (12+1)*2
Answer:
m = 5/2
OR
m = 2 1/2
OR
m = 2.5
Step-by-step explanation:
