Let s = the speed of the slower train in km/hrs+10 = the speed of the faster train in km/hrLet t = time in hrs for the slower train to go 160 kmt-5 = time in hrs for faster train to go 160 km---------------Slower train:(1)
160=s.t
Faster train:(2) 160=(s+10) .(t-.5)From (1)(1) t=160/s
use the relations given in following screenshot and then use quadratic equation.
If anything is in parentheses do that first, however if there isn’t you always do exponents next so evaluate 6 squared
Hope this helps!!
Answer:
i try my best to find the answer if i can give me some time when i will find then i will tell you
Step-by-step explanation:
Answer:
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Terms/Coefficients
- Factoring
Step-by-step explanation:
<u>Step 1: Define</u>
<u>Step 2: Simplify</u>
- [Fraction] Factor numerator:
- [Fraction] Factor denominator:
- [Fraction] Divide:
Answer:
0.32
Step-by-step explanation:
You can convert -2/5 to -0.4. Then multiply them together to get 0.32. Remember that multiplying two negatives makes a positive. Hope this helps :)
