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3 years ago

How to search for the largest files on my computer vista?

1 answer:

5 0

To find the largest files on your computer using Explorer, open Computer and click up in the search box. When you click inside of it, a little window pops up below with a list of your recent searches and then a add search filter option.

Go ahead and click on Size and then you’ll get another menu with a couple of options:

Go ahead and pick something like Large, Huge or Gigantic otherwise you will get a list of way too many files. If you just want to see larger files, I suggest choosing huge or gigantic. Then just press enter without typing in anything else.

Alternatively, drop to command prompt type cd\

dir /s/o:s to get a listing in ascending order.

for descending order dir /s/o:-s

Since there might be a lot of files you might want to pipe it into a text file, simply add > largefiles.txt

dir /s/o:-s > c:\temp\largefiles.txt (the c:\temp directory must exist, if not the command will fail. Once you're on the root with cd\ just create the temp directory with md c:\temp or via the GUI, alternatively, again add & md c:\temp into the dir command)

If you want to get fancy you can also just open the results with the &

dir /s/o:-s > c:\temp\largefiles.txt & notepad c:\temp\largefiles.txt

Please Note:

(the c:\temp directory must exist, if not the command will fail. Once you're on the root with cd\ just create the temp directory with md c:\temp or via the GUI, alternatively, again add & md c:\temp into the dir command)

md c:\temp\ & dir /s/o:-s > c:\temp\largefiles.txt & notepad c:\temp\largefiles.txt

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int main() {

string simon_Pattern;

string user_Pattern;

int userScore;

int i;

user_Score = 0;

simon_Pattern = "RRGBRYYBGY";

user_Pattern = "RRGBBRYBGY";

for (i = 0; i <= simson_pattern.length; i++) {

if (simon_Pattern[i] == user_Pattern[i]) {

user_Score = user_Score + 1;

} else {

break;

}

cout << "userScore: " << user_Score << endl;

return 0;

}

Here it uses two string variable to store “simson’s pattern and user’s pattern”. Then a “for loop” is executed till the end of the string. Inside the for loop both the strings are compared character by character and when found the score is added. If not for loop is exited and finally the score is displayed.

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3 years ago

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1. While cell phones provide Freedom and mobility,they can also become a leash, compelling user's to answer them anywhere and an

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Cellular phones have had a major impact on our lives and the way that we perform every day tasks. Many of these changes are apparent, while others we may not even be aware of.

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3 years ago

How does so called marshalling solve the problem of different byte ordering of sender and receiver? 8. What is the purpose of a

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Marshalling solve the problem of different byte ordering of sender and receiver by:

By the use of Common Object Request Broker Architecture (CORBA):

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2 years ago

An employee was watching Jessica, an IT employee, typing in many different confusing terms. Jessica explained that she needed to

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3 years ago

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When an author produce an index for his or her book, the first step in this process is to decide which words should go into the

Igoryamba

Answer:

import string

dic = {}

book=open("book.txt","r")

# Iterate over each line in the book

for line in book.readlines():

tex = line

tex = tex.lower()

tex=tex.translate(str.maketrans('', '', string.punctuation))

new = tex.split()

for word in new:

if len(word) > 2:

if word not in dic.keys():

dic[word] = 1

else:

dic[word] = dic[word] + 1

for word in sorted(dic):

print(word, dic[word], '\n')

book.close()

Explanation:

The code above was written in python 3.

import string 

Firstly, it is important to import all the modules that you will need. The string module was imported to allow us carry out special operations on strings.

dic = {}

book=open("book.txt","r")

# Iterate over each line in the book

for line in book.readlines():

tex = line

tex = tex.lower()

tex=tex.translate(str.maketrans('', '', string.punctuation))

new = tex.split()

An empty dictionary is then created, a dictionary is needed to store both the word and the occurrences, with the word being the key and the occurrences being the value in a word : occurrence format.

Next, the file you want to read from is opened and then the code iterates over each line, punctuation and special characters are removed from the line and it is converted into a list of words that can be iterated over.

 for word in new:

if len(word) > 2:

if word not in dic.keys():

dic[word] = 1

else:

dic[word] = dic[word] + 1

For every word in the new list, if the length of the word is greater than 2 and the word is not already in the dictionary, add the word to the dictionary and give it a value 1.

If the word is already in the dictionary increase the value by 1.

for word in sorted(dic):

print(word, dic[word], '\n')

book.close()

The dictionary is arranged alphabetically and with the keys(words) and printed out. Finally, the file is closed.

check attachment to see code in action.

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3 years ago