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ryzh [129]
2 years ago
11

Can you help me solve -3(y-4)=18

Mathematics
2 answers:
VikaD [51]2 years ago
6 0
First you have to distribute. -3y +12=18.  -3y=6. y= -2.
svp [43]2 years ago
6 0
First divide -3 by both sides.  so then you will have (y-4)= -6 then you take the parenthesis away. y-4=-6 Now you add 4 to each side because addition is the opposite of subtraction. y= -6 + 4 which then becomes y= -2
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2 years ago
Help with this one because I do not know how to do perpendicular plz put explanation with steps worth 50!
Yuri [45]

Answer:

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line 2x-3y=12 is 3x+2y=34  

Step-by-step explanation:

Given:  

2x-3y=12  

To Find:  

Equation of line passing through ( 16, -7) and is perpendicular to the line  

2x-3y=12  

Solution:  

2x-3y=12 ...........Given  

\therefore y=\dfrac{2}{3}\times x-4

Comparing with,  

y=mx+c  

Where m =slope  

We get  

Slope = m1 = \dfrac{2}{3}  

We know that for Perpendicular lines have product slopes = -1.

m1\times m2=-1

Substituting m1 we get m2 as

\dfrac{2}{3}\times m2=-1\\\\m2=-\dfrac{3}{2}

Therefore the slope of the required line passing through (16 , -7) will have the slope,

m2=-\dfrac{3}{2}  

Now the equation of line in slope point form given by  

(y-y_{1})=m(x-x_{1})  

Substituting the point (16 , -7) and slope m2 we will get the required equation of the line,  

(y-(-7))=-\dfrac{3}{2}\times (x-16)\\\\2y+14=-3x+48\\3x+2y=34......Equation\ of\ line  

Therefore, equation of the line that passes through (16,-7) and is perpendicular to the line  2x-3y=12 is

3x+2y=34  

3 0
3 years ago
Can someone help me with this problem and show your work
zloy xaker [14]
55 degrees

The supplementary angle is 55 because 180-125=55

Then subtract the interior angles 180-75-55=55
3 0
2 years ago
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