Question

Select TWO possible values for x in the equation x2=45.

Answer 1

Answer:

$3 \sqrt 5}$  and $-3 \sqrt 5}$

Step-by-step explanation:

Given

$x^2 = 45$

Required

Determine the values of x

$x^2 = 45$

Take square root of both sides

$\sqrt{x^2} = \±\sqrt{45}$

$x = \±\sqrt{45}$

Expand 45 as 9 * 5

$x = \±\sqrt{9 * 5}$

Split the square root

$x = \±(\sqrt{9} *\sqrt 5}$

$x = \±3 *\sqrt 5}$

$x = \±3 \sqrt 5}$

This can be further split to:

$x = 3 \sqrt 5}$ or $x = -3 \sqrt 5}$

Hence, the possible values of x are

$3 \sqrt 5}$  and $-3 \sqrt 5}$