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guajiro [1.7K]
4 years ago
9

Evaluate 6t−20−32u when t=6 and u=1/4

Mathematics
2 answers:
MissTica4 years ago
5 0

Answer:


Step-by-step explanation8

dsp734 years ago
3 0
6t - 20 - 32u
When t = 6, u = 1/4
6(6) - 20 - 32(1/4)
36 - 20 - 8
16 - 8
8
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stepladder [879]

the answer is b i did the math it checks out

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What number would be ten times greater than 0.05?
Nastasia [14]

Answer:

0.5?

Step-by-step explanation:

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In circle S, what is the value of x? <br><br><br> Enter your answer in the box. x = °
nevsk [136]
We are asked to solve for the value of "x" in the problem. In the circle property, assuming that S is the diameter of the circle, we can say that the angle facing the diameter is 90°.

We have the summation of all angles in a triangle equal to 180°. Solving for x, we have:
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3 years ago
Find the angle that the line through the given pair of points makes with the positive direction of the x-axis
alexdok [17]

Answer:

Therefore the angle that the line through the given pair of points makes with the positive direction of the x-axis is 45°.

Step-by-step explanation:

Given:

Let

A(x₁ , y₁) = (1 , 4) and  

B( x₂ , y₂ ) = (-1 , 2)

To Find:

θ = ?

Solution:

Slope of a line when two points are given is given bt

Slope(AB)=\dfrac{y_{2}-y_{1} }{x_{2}-x_{1} }

Substituting the values we get

Slope(AB)=\dfrac{2-4}{-1-1}=\dfrac{-2}{-2}=1\\\\Slope=1

Also Slope of line when angle ' θ  ' is given as

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tan 45 = 1

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3 years ago
In each part (a)-(d) below, some additional assumptions about the
Viktor [21]

In the triangle, the fact that wee are given 2AX = 3XD isn't enough to prove similarity.

<h3>How to explain the triangle?</h3>

a. In the question, we are given 2AX = 3XD. An arbitrary triangle AXB can be drawn where one extends AX and choose a point D on the extended line in order for 2AX = 3XD. Also, extend BX and choose a point C on the line so that 2BX = XC. Even though they both satisfy the condition, they're not similar.

b. We are given that AX/BX = DX/CX. When this is rearranged, we'll have AX/DX = BX/CX. In this case, let AX/DX = k. DX and AX will align upon rotation of 180°. The triangle can then be dilated by a factor of k. This brings about the mapping of triangle DXC to AXB. Therefore, the original triangle DXC is similar to AXB.

c. Lines AB and CD are parallel. Here, the dilation moves line CD onto line AB. Here, since the dilation moves D to a point on ray XA, D must move to A. Therefore, the rotation of triangle DXC is similar to AXB. Therefore, DXC is similar to AXB.

d. Here, angle XAB is congruent to angle XCD. This shows similarity and in this case, XCD is similar to XAB.

Learn more about triangles on:

brainly.com/question/28021872

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