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Mariulka [41]
3 years ago
8

A train leaves Miami at 3:00 PM. A second train leaves the same city in the same direction at 5:00 PM. The second train travels

50mph faster than the first. If the second train overtakes the first at 7:00 PM, what is the speed of each of the two trains?
Mathematics
1 answer:
NISA [10]3 years ago
6 0

Answer: the speed of the first train is 50 mph.

The speed of the second train is 100 mph.

Step-by-step explanation:

Let x represent the speed of the first train. The second train travels 50mph faster than the first. It means that the speed of the second train is (x + 50) mph.

Distance = speed × time

If the second train overtakes the first at 7:00 PM, it means that both trains covered the same distance by 7:00 PM. The first train left Miami at 3:00PM. Time spent by the first train is 7 - 3 = 4 hours

Distance covered by the first train in 4 hours is 4x

The second train left at 5:00 PM. Time spent by the second train is 7 - 5 = 2 hours

Distance covered by the second train in 2 hours is 2(x + 50)

Therefore,

4x = 2(x + 50)

4x = 2x + 100

4x - 2x = 100

2x = 100

x = 100/2

x = 50 mph

The speed of the second train is

x + 50 = 50 + 50 = 100 mph

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\quad \huge \quad \quad \boxed{ \tt \:Answer }

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____________________________________

\large \tt Solution  \: :

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\qquad \tt \rightarrow \:y-y_1 = m(x - x_1)

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Here :

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Dennis_Churaev [7]

Answer:

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Step-by-step explanation:

You only need two points on a line to find the equation for that line.

We are going to use 2 points that cross that line or at least come close to. You don't have to use the green points... just any point on the line will work.  You might have to approximate a little.

I see ~(67.5,67.5) and ~(64,65).

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You may use \frac{y_2-y_1}{x_2-x_1} where (x_1,y_1) \text{ and } (x_2,y_2) are points on the line.

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--------------------

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3 years ago
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<h3>Answer: $26.62 </h3>

============================

Work Shown:

P = 20 is the amount deposited

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