4 years ago

Jordan drew a shape. The shape had 3 unequal angles. What shape could Jordan have drawn?

Mathematics

1 answer:

anygoal [31]4 years ago

6 0

Jordan drew a Scalene Triangle

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A triangle has a side lengths of 3 centimeters, 5 centimeters, and 4 centimeters. Abe used converse of the Pythagorean Theorem t

fgiga [73]

No, Abe is incorrect.

If you don’t know which side is the hypotenuse, you have to try every possibility.

3^ + 4^ = 5^
25 = 25

The triangle is a right triangle. The side which is 5 cm long is the hypotenuse.

8 0

3 years ago

Which expression is equivalent

Tatiana [17]

Given expression is

$\sqrt[4]{\frac{16x^{11}y^8}{81x^7y^6}}$

Radical is fourth root

first we simplify the terms inside the radical

$\frac{x^{11}}{x^7}=x^4$

$\frac{y^(8)}{y^6}=y^2$

So the expression becomes

$\sqrt[4]{\frac{16x^4y^2}{81}}$

Now we take fourth root

$\sqrt[4]{16} = 2$

$\sqrt[4]{81} = 3$

$\sqrt[4]{x^4} = x$

We cannot simplify fourth root (y^2)

After simplification , expression becomes

$\frac{2x\sqrt[4]{y^2}}{3}$

Answer is option B

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3 years ago

Please help me with this

larisa [96]

Please Show a picture or either a text so that I can help you

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3 years ago

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Ax+bx-c=0 x= _/(a __)

Ulleksa [173]

Ax+bx−c=0

Step 1: Add c to both sides.

ax+bx−c+c=0+c

ax+bx=c

Step 2: Factor out variable x.

x(a+b)=c

Step 3: Divide both sides by a+b.

x(a+b)a+b=ca+b

x=ca+b

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3 years ago

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Please help me this question

postnew [5]

Let's split it into rectange and tringle
BC= 2.1+ sqrt(3.2^2 - 1.9^2) = 4.67

7 0

3 years ago

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