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3 years ago

Please help me!

Mathematics

1 answer:

umka2103 [35]3 years ago

7 0

Answer:

C(m) = 0.10x + 41

Step-by-step explanation:

C(m) = 0.10m + 41

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Plot two points that are 777 units from Point \blueD{D}Dstart color #11accd, D, end color #11accd and also share the same xxx-co

Karolina [17]

Right format of question:

Plot two points that are 7 units from Point D and also share the same x-coordinate as Point D.

Answer:

$D' = (-4,-6)$ and $D' = (-4,8)$

Step-by-step explanation:

Given

$D(x,y) = (-4,1)$

Required

Determine a point 7 points from D and in the same x coordinate

Represent this point with D'.

From the requirement of the question, D' has two possible values and these values are:

$D' = D(x,y-7)$ ----> 7 units down and

$D' = D(x,y+7)$ ----> 7 units up

Substitute values for x and y in $D' = D(x,y-7)$ and $D' = D(x,y+7)$

So, we have:

$D' = D(x,y-7)$

$D' = (-4,1 - 7)$

$D' = (-4,-6)$

$D' = D(x,y+7)$

$D' = (-4,1+7)$

$D' = (-4,8)$

3 0

3 years ago

WILL GIVE BRAINLIEST IF CORRECT!!!!

Rzqust [24]

I think it would me 568 m

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2 years ago

Solve for A: B = 2/5 ( A-9)

tamaranim1 [39]

Answer:

Step-by-step explanation:

B = 2/5(A - 9)

(5/2)B = A - 9

A = 9 + (5/2)B

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2 years ago

Which formula gives the x-coordinates of the maximum values for y = cos(x)?

solong [7]

We have been given a function $y=\cos(x)$ . We are asked to find the formula which gives the x-coordinates of the maximum values for given function.

We know that cosine function oscillates between $-1$ and 1 that is minimum value of cosine is $-1$ and maximum value is $1$ .

We also know that $\cos(0)=1$ and after period of cosine is $2\pi$ . This means after every $2\pi$ , we will get to $1$ .

So maximum of cosine is $2\pi n$ , where n is an integer.

Therefore, our required formula is $2\pi n$ , where, $n=0,\pm 1,\pm 2,\pm3,...$

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3 years ago

3x + ky = 8

sattari [20]

Answer:

(a): x is 3 and ky is -1

(b): k is -2

Step-by-step explanation:

Let: 3x + ky = 8 be equation (a)

x - 2 ky = 5 be equation (b)

Then multiply equation (a) by 2:

→ 6x + 2ky = 16, let it be equation (c)

Then equation (c) + equation (b):

${ \sf{(6 + 1)x + (2 - 2)ky = (16 + 5)}} \\ { \sf{7x = 21}} \\ { \sf{x = 3}}$

Then ky :

${ \sf{2ky = 3 - 5}} \\ { \sf{ky = - 1}}$

${ \bf{y = \frac{1}{2} }} \\ { \sf{ky = - 1}} \\ { \sf{k = - 2}}$

4 0

3 years ago