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Nuetrik [128]
3 years ago
7

Geometry! Please help!

Mathematics
2 answers:
Leona [35]3 years ago
6 0
The height of the trapezoid is 3cm. Let me know if you would like an explanation!
Rus_ich [418]3 years ago
3 0

Answer: The height of the trapezoid is 3 cm.

Step-by-step explanation:

Since we have given that

There is a trapezoid over the rectangle.

Dimensions of rectangle is as follows:

Length = 5 cm

Breadth = 13 cm

So, Area of rectangle would be

Length\times breadth\\\\=5\times 13\\\\=65\ sq.\ cm

Dimensions of trapezoid as follows:

Length of two parallel sides are 'a' = 11 cm

and 'b' = 13 cm

So, Area of trapezoid would be

\dfrac{1}{2}\times (a+b)\times h\\\\=\dfrac{1}{2}\times (11+13)\times h\\\\=\dfrac{1}{2}\times 24\times h\\\\=12\times h

Since the total area of composite shape = 101 sq. cm

Area of composite shape = Area of trapezoid + Area of rectangle

101=65+12h\\\\101-65=12h\\\\36=12h\\\\\dfrac{36}{12}=h\\\\h=3\ cm

Hence, the height of the trapezoid is 3 cm.

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Bezzdna [24]

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8 0
3 years ago
NEED HELP ASAP, I WILL GIVE YOU BRAINLIEST
tresset_1 [31]

Answer:

0.9412

Step-by-step explanation:

Ultimately, if you know the length of the arc, and you know the length of the radius, the central angle (in radians) is just how many radii long the arc is. angle=arc lengthradius length=16 feet17 feet≈0.9412.

8 0
3 years ago
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Morgarella [4.7K]
I think is
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5 0
3 years ago
A water fountain shoots up a jet of water
notsponge [240]
Could possibly be a geyser

3 0
3 years ago
Helen's house is located on a rectangular lot that is1 1-8 miles by 9/10 mile.Estimate the distance around the lot
klemol [59]

Answer: The distance around the lot is given by

4\frac{1}{20}\ miles

Step-by-step explanation:

Since we have given that

Length of rectangular lot is given by

1\frac{1}{8}\\\\=\frac{9}{8}\ miles

Width of rectangular lot is given by

\frac{9}{10}\ mile

We need to find the distance around the lot.

As we know the formula for "Perimeter of rectangle":

Perimeter=2(Length+Width)\\\\Perimeter=2(\frac{9}{8}+\frac{9}{10})\\\\Perimeter=2(\frac{45+36}{40})\\\\Perimeter=2\times \frac{81}{40}\\\\Perimeter=\frac{81}{20}\\\\Perimeter=4\frac{1}{20}\ miles

Hence, the distance around the lot is given by

4\frac{1}{20}\ miles


3 0
3 years ago
Read 2 more answers
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