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Annette [7]
4 years ago
5

Calculate the acceleration of the object during the first two seconds

Physics
1 answer:
Ksenya-84 [330]4 years ago
3 0

Answer:

The acceleration of the object during the first two seconds  is 1.5 \frac{m}{s^{2} }.

Explanation:

At t = 2 s, velocity of the object is 3 m/s

At t = 0 s, velocity of the object is 0 m/s

Acceleration is define as rate of change of velocity with time.

∴Acceleration = \frac{v_{f} -v_{i} }{t_{f} - t_{i}  }

Acceleration = \frac{v_{2} -v_{0} }{t_{2} - t_{0}  }

Acceleration = \frac{3-0 }{2-0  }

Acceleration = 1.5 \frac{m}{s^{2} }

The acceleration of the object during the first two seconds  is 1.5 \frac{m}{s^{2} }.


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Answer:

Unmeltedd ice = 308.109 g

Explanation:

Gibbs Free energy:

A systems Gibbs Free Energy is defined as the free energy of the product of the absolute temperature and the entropy change less than the enthalpy change.

Therefore, G = ΔH-TΔS

where G is Gibbs Free Energy

          ΔH is enthalpy change

          T is absolute temperature

          ΔS is entropy change

Here since there is a phase change, therefore G will be 0.

∴ΔH = TΔS

Given: Temperature, T = 0°C = 273 K

           Entropy change,ΔS = 600 J/K

           Latent heat of fusion of water = 333 J/g

∴ΔH = TΔS

  ∴ΔH = 273 x 600

           = 163800 J

So this is the amount of enthalpy that will be used into melting of ice.

  ∴ΔH = mass of ice melted x latent heat of fusion of water

    Mass of ice melted = ΔH / latent heat of fusion of water

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This is the mass of ice melted.

And initial amount of ice is 800 g

Amount of ice left after melting = Initial amount of ice - amount of ice melted

                                                   = 800-491.891

                                                  = 308.109 g

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8 0
3 years ago
An airplane flies with a velocity of 55.0 m/s [ 35° N of W] with respect to the air (this is
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Explanation:

The computation of the wind velocity is shown below:

But before that, we need to find out the angles between the vectors

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v^2 = 55^2 + 40^2 - 2 · 55 · 40 · cos 18°

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v = √440.6

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≈ 21 m/s

Hence, The wind velocity is 21 m/s.  

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