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Annette [7]
4 years ago
5

Calculate the acceleration of the object during the first two seconds

Physics
1 answer:
Ksenya-84 [330]4 years ago
3 0

Answer:

The acceleration of the object during the first two seconds  is 1.5 \frac{m}{s^{2} }.

Explanation:

At t = 2 s, velocity of the object is 3 m/s

At t = 0 s, velocity of the object is 0 m/s

Acceleration is define as rate of change of velocity with time.

∴Acceleration = \frac{v_{f} -v_{i} }{t_{f} - t_{i}  }

Acceleration = \frac{v_{2} -v_{0} }{t_{2} - t_{0}  }

Acceleration = \frac{3-0 }{2-0  }

Acceleration = 1.5 \frac{m}{s^{2} }

The acceleration of the object during the first two seconds  is 1.5 \frac{m}{s^{2} }.


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