Question

The local animal shelter throws a dog-themed party. Humans, h, and dogs, d are both invited. The event space imposes two restrictions on the party: there can only be 120 dogs and humans combined, and, to keep things manageable, there must be 1 human to every 3 dogs. This situation can be represented by a system of two linear equations. One of these equations is given. Write the second equation in the box.
d/3=h

Answer 1

What type of math is this problem? Is it advanced?

Answer 2

Answer:

The required equation is $d+h=120$

Step-by-step explanation:

Given : The local animal shelter throws a dog-themed party. Humans, h, and dogs, d are both invited. The event space imposes two restrictions on the party: there can only be 120 dogs and humans combined, and, to keep things manageable, there must be 1 human to every 3 dogs.

To find : Second equation from the situation?

Solution :

We have given,

'h' represent the humans,

'd' represent the dogs.

There must be 1 human to every 3 dogs.

So, One equation is $\frac{d}{3}=h$ (given)

According to question,

There can only be 120 dogs and humans combined.

i.e. The required equation is $d+h=120$

Therefore, The event space imposes two restrictions on the party are

Equation 1 - $\frac{d}{3}=h$

Equation 2 - $d+h=120$