<span>the height of an equilateral triangle = s</span>√3/2
Answer:
see explanation
Step-by-step explanation:
To find the zeros let h(t) = 0, that is
t² + 4t + 3 = 0 ← in standard form
(t + 3)(t + 1) = 0 ← in factored form
Equate each factor to zero and solve for t
t + 3 = 0 ⇒ t = - 3 ← smaller t
t + 1 = 0 ⇒ t = - 1 ← larger t
(2)
given a parabola in standard form : ax² + bx + c ( a ≠ 0)
Then the x- coordinate of the vertex is
= - 
h(t) = t² + 4t + 3 ← is in standard form
with a = 1 and b = 4, thus
= - 
= - 2
Substitute t = - 2 into h(t) for y- coordinate
h(- 2) = (- 2)² + 4(- 2) + 3 = 4 - 8 + 3 = - 1
Vertex = (- 2, - 1 )
Answer:
all the statements are true
Step-by-step explanation:
The acute triangle is the triangle in which all the angles are less than 90°
While on the other hand, the equilateral triangle is the triangle in which all the angles are of 60° so this also makes the acute triangle
Given that
p = Acute triangle
q = equilateral triangle
Based on the above explanation
The conditions are as follows
p ∨ q is true, the ∨ refers “or” condition, so if any of either statement is true then the statement is true
p ∧ q is also true, the ∧ refers that both the statements should be true.
The arrows on the left and right indicate "implies," and that is true if and only if the p is false or q is true. Both p and q are valid for both the right and the left arrows
The last means equal and is valid if both p and q are the same as they are, so that is true too.
Hence, all the statements are true
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Step-by-step explanation:lu7iy 6t5r47oe;8jo/ilni.ub8yu
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