Answer:
3(5x - 2)
Step-by-step explanation:
Answer:



Step-by-step explanation:
Given




Required
The dimension that minimizes the cost
The volume is:

This gives:

Substitute 


Make H the subject


The surface area is:
Area = Area of Bottom + Area of Sides
So, we have:

The cost is:



Substitute:
and 



To minimize the cost, we differentiate

Then set to 0


Rewrite as:

Divide both sides by W

Rewrite as:

Solve for 


Take cube roots

Recall that:







Hence, the dimension that minimizes the cost is:



<span>Square root of 100 is a rational number. Because sqaure rooot 100 = 10. And, 10 can be written in the form rational number. Any number that can be written in the form of p/q where p and q are integers and q in not zero is called a rational number.</span>
Answer:
do 3 divided by 10 to get the decimal
Step-by-step explanation:
Answer: $ 3462.03
Step-by-step explanation:
The exponential equation for growth (compounded continuously) is given by :-

, where P= Present value
r= growth rate ( in decimal)
t= time
As per given , we have
P=$1900, r = 6% =0.06 and t= 10
Substitute all the values in the above equation , we get


[To the nearest cent]
Hence, the balance in the account after 10 years = $ 3462.03