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3 years ago

About how many laps around the perimeter of the field would equal 1 mile? Explain

1 answer:

8 0

So if you run around the outside of the enfield, it would take a little more than 5 laps to reach one mile. If you cut across at the goal line, you lap would only be 306.6 yards and it would take 5.74 laps to reach 1 mile

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What is the irrational number in This set: 12.89, square root of 12 and 12/144 ?

kifflom [539]

Good night,

Irrational numbers are those that can't be expressed as a fraction:

12.89 can be expressed as: $\frac{1289}{100}$

$\frac{12}{144}= \frac{1}{12}$

The above numbers can be expressed as a fraction, then the logical answer is: $\sqrt{12}$

But we will check the answer:

$\sqrt{12}= \sqrt{2^{2}*3 } =2* \sqrt{3} =3.4641016...$

As you can see we can't express that number as a fraction, so that is te correct answer.

6 0

3 years ago

Which type of factoring is used to factor the following expression: 2x^2 + 7x- 30

svetlana [45]

Answer:

(2x - 5) • (x + 6)

7 0

3 years ago

a city doubles its size every 64 years. if the population is currently 225,000 what will the population be in 128 years

ale4655 [162]

Answer:

450,000

Step-by-step explanation:

128/64:2

225,000 X 2: 450,000

4 0

2 years ago

Read 2 more answers

Patti earns $13.50 per hour. She is offered a raise of 7% increase per hour. After the raise,how much will Patti make per hour?

scoray [572]

20.50 is the amount patti is making per hour

3 0

2 years ago

3^x= 3*2^x solve this equation

kompoz [17]

In the equation

$3^x = 3\cdot 2^x$

divide both sides by $2^x$ to get

$\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3$

Take the base-3/2 logarithm of both sides:

$\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}$

Alternatively, you can divide both sides by $3^x$ :

$\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13$

Then take the base-2/3 logarith of both sides to get

$\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}$

(Both answers are equivalent)

8 0

2 years ago