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telo118 [61]
3 years ago
12

Answers plz it’s timed!!

Mathematics
1 answer:
expeople1 [14]3 years ago
5 0
Here are the answers i’m order from top to bottom 12x/5 , 12x+5, 12x-5
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What is the percent change from 46 to 7? Round to the nearest tenth
Mashcka [7]
-84.8 is with it rounded to the nearest tenth
6 0
3 years ago
Read 2 more answers
Simplify the expression -3z(1.8z-2.2).
alexdok [17]

Answer:

- 5.4z {}^{2}  + 6.6z

Step-by-step explanation:

Given:

-3z(1.8z-2.2)

Solution:

Applying Distributive property,we obtain

  • (−3z)(1.8z)+(−3z)(−2.2)

Simplifying using PEMDAS:

  • - 5.4z {}^{2}  + 6.6z

Done!

5 0
2 years ago
Lakshmi donates 20% of her income to charity. What fraction of her income does Lakshmi donate to charity?
777dan777 [17]

1/5

Hope this helps :)


5 0
3 years ago
In triangle KLM, if K is congruent to L, KL = 9x - 40, LM = 7x - 37, & KM = 3x + 23, find x & the measure of each angle.
Dennis_Churaev [7]

Answer: x = 15, ∠K = 45.7°, ∠L = 45.7°, ∠M = 88.6°

<u>Step-by-step explanation:</u>

Since ∠K ≅ ∠L, then ΔKLM is an isoceles triangle with base KL

 KM ≅ LM

3x + 23 = 7x - 37

       23 = 4x - 37

       60 = 4x

        15 = x

KM = LM = 3x + 23

               = 3(15) + 23

               = 45 + 23

               = 68

KL = 9x - 40

    = 9(15) - 40

    = 135 - 40

    = 95

Next, draw a perpendicular bisector KN from K to KL. Thus, N is the midpoint of KL and ΔMNL is a right triangle.

  • Since N is the midpoint of KL and KL = 95, then NL = 47.5
  • Since ∠N is 90°, then NL is adjacent to ∠l and ML is the hypotenuse

Use trig to solve for ∠L (which equals ∠K):

cos ∠L = \frac{adjacent}{hypotenuse}

cos ∠L = \frac{47.5}{68}

      ∠L = cos⁻¹ (\frac{47.5}{68})

      ∠L = 45.7  

Triangle sum Theorem:

∠K + ∠L + ∠M = 180°    

45.7 + 45.7 + ∠M = 180

       91.4     + ∠M = 180

                      ∠M = 88.6

       

7 0
3 years ago
Simplify the imaginary number sqr -75
m_a_m_a [10]

Answer:

5i\sqrt{3}

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

and \sqrt{-1} = i

Given

\sqrt{-75}

= \sqrt{25(3)(-1)}

= \sqrt{25}  × \sqrt{3} × \sqrt{-1}

= 5 × \sqrt{3} × i

= 5i\sqrt{3}

3 0
3 years ago
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