I think that would be a rectangle with sides 13 and 8 Which = 104 ins^2
Answer:
14x^-10x+12+2=-140x+14
Step-by-step explanation:
Very simple. Just add/multiply the like terms, (14x^-10x & 12+2), and then you'll get the answer, but since 140x and 14 are not like terms, the answer stays as 140x+14.
Well, 1x5=5 and 2x5=10 so 3x5=15
Answer:
- 892 lb (right)
- 653 lb (left)
Step-by-step explanation:
The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...
Rcos(45°) +Lcos(75°) = 800
Rsin(45°) -Lsin(75°) = 0
Solving these equations by Cramer's Rule, we get ...
R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))
= 800sin(75°)/sin(120°) ≈ 892 . . . pounds
L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds
The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.
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This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...
(right, left) = w/sin(α+β)×(sin(β), sin(α))
16 students turned in their homework early i think. I hope this helps
