Why is cos(nπ) = (–1)n true, when n could be any integer?
2 answers:
its true because -1 to even power is positive, -1 to odd power is negative
Answer:
Given, ![cos\,n\pi=(-1)^n](https://tex.z-dn.net/?f=cos%5C%2Cn%5Cpi%3D%28-1%29%5En%20)
We state why it is true.
Lets check for some values of n.
for n = 0
⇒ ![cos\,0=(-1)^0=1](https://tex.z-dn.net/?f=cos%5C%2C0%3D%28-1%29%5E0%3D1)
for n = 1
⇒ ![cos\,\pi=(-1)^1=-1](https://tex.z-dn.net/?f=cos%5C%2C%5Cpi%3D%28-1%29%5E1%3D-1)
for n = -1
⇒ ![cos\,-\pi=(-1)^{-1)=-1](https://tex.z-dn.net/?f=cos%5C%2C-%5Cpi%3D%28-1%29%5E%7B-1%29%3D-1)
for n = 2
⇒ ![cos\,2\pi=(-1)^{2)=1](https://tex.z-dn.net/?f=cos%5C%2C2%5Cpi%3D%28-1%29%5E%7B2%29%3D1)
for n = -2
⇒ ![cos\,-2\pi=(-1)^{-2)=1](https://tex.z-dn.net/?f=cos%5C%2C-2%5Cpi%3D%28-1%29%5E%7B-2%29%3D1)
So, Its clear from above . value of cos nπ is either 1 or -1.
value of cos nπ is 1 when n is even integer and -1 when n is odd integer.
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