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Mkey [24]
3 years ago
14

A number y multiplied by −3 is less than −2/5. Write this word sentence as an inequality.

Mathematics
1 answer:
bazaltina [42]3 years ago
8 0
The answer is -3y < -2/5
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Please answer this, thanks :)
Kipish [7]

Answer:

D

Step-by-step explanation:

If you add one to both of the sides of the first rectangle you will get the second rectangles numbers which makes it similar.

5 0
2 years ago
Please help me<br><br> In circle Y, what is mTU?<br><br> 59°<br> 67°<br> 71°<br> 118°
yawa3891 [41]

we know that

The measure of the angle formed by 2 chords that intersect inside the circle is \frac{1}{2} the sum of the chords' intercepted arcs. (Angles of intersecting chords theorem)

so

in this problem

63=\frac{1}{2}*(SR+TU)\\ \\ 63=\frac{1}{2}*(55+TU)\\ \\ TU=63*2-55\\ \\ TU=126-55\\ \\ TU=71

therefore

the answer is

The measure of the arc TU is equal to 71degrees


8 0
3 years ago
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consider The line that passes through each pair of given points and decide what type of slope the line has.​
Dominik [7]

Answer:

so you play gacha too...

8 0
3 years ago
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If cos theta = 3/5 and theta is in quadrant 4, tan 2 theta =
Neko [114]

Answer:

16/9.

Step-by-step explanation:

I am assuming you mean tan^2 theta.

The adjacent side of the triangle drawn in Q 4 = 3 (as cos theta = 3/5.

The opposite side of the triangle drawn in Q 4 = sqrt(5^2-3^2) = 4.

The tangent is negative in Q 4

So tan theta = -4/3.

tan^2 theta = 16/9.

7 0
3 years ago
What is the solution to 2 log Subscript 9 Baseline (x) = log Subscript 9 Baseline 8 + log Subscript 9 Baseline (x minus 2) x = n
Kaylis [27]

Answer:

\large\boxed{\large\boxed{x=4}}

Step-by-step explanation:

The equation to solve is:

            2\log_9 x=\log_9 8+\log_9 (x-2)

1. <u>On the left-hand side </u>use: "The product of a constant by a logarithm is equal to the logarithm raised to the constant"

Thus, the left-hand side is:

               2\log_9 x=\log_9 x^2

2. On the <u>right-hand side</u> use "The sum of two logarithms with the same base is the logarithm of the product":

Then, on the right-hand side:

        \log_9 8+\log_9 (x-2)=\log_9 8(x-2)

3. <u>Make them equal</u>:

      \log_9 x^2=\log_9 8(x-2)

4. Since the two functions are the same, <u>make the arguments equal</u>:

     x^2=8(x-2)

5. <u>Solve the equation</u>:

        x^2=8x-16\\\\x^2-8x+16=0\\\\(x-4)^2=0\\\\x-4=0\\\\x=4\leftarrow solution

4 0
3 years ago
Read 2 more answers
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