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3 years ago

A number y multiplied by −3 is less than −2/5. Write this word sentence as an inequality.

Mathematics

1 answer:

bazaltina [42]3 years ago

8 0

The answer is -3y < -2/5

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Please answer this, thanks :)

Kipish [7]

Answer:

Step-by-step explanation:

If you add one to both of the sides of the first rectangle you will get the second rectangles numbers which makes it similar.

5 0

2 years ago

Please help me In circle Y, what is mTU? 59° 67° 71° 118°

yawa3891 [41]

we know that

The measure of the angle formed by $2$ chords that intersect inside the circle is $\frac{1}{2}$ the sum of the chords' intercepted arcs. (Angles of intersecting chords theorem)

in this problem

$63=\frac{1}{2}*(SR+TU)\\ \\ 63=\frac{1}{2}*(55+TU)\\ \\ TU=63*2-55\\ \\ TU=126-55\\ \\ TU=71$

therefore

the answer is

The measure of the arc TU is equal to $71degrees$

8 0

3 years ago

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consider The line that passes through each pair of given points and decide what type of slope the line has.

Dominik [7]

Answer:

so you play gacha too...

8 0

3 years ago

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If cos theta = 3/5 and theta is in quadrant 4, tan 2 theta =

Neko [114]

Answer:

16/9.

Step-by-step explanation:

I am assuming you mean tan^2 theta.

The adjacent side of the triangle drawn in Q 4 = 3 (as cos theta = 3/5.

The opposite side of the triangle drawn in Q 4 = sqrt(5^2-3^2) = 4.

The tangent is negative in Q 4

So tan theta = -4/3.

tan^2 theta = 16/9.

7 0

3 years ago

What is the solution to 2 log Subscript 9 Baseline (x) = log Subscript 9 Baseline 8 + log Subscript 9 Baseline (x minus 2) x = n

Kaylis [27]

Answer:

$\large\boxed{\large\boxed{x=4}}$

Step-by-step explanation:

The equation to solve is:

$2\log_9 x=\log_9 8+\log_9 (x-2)$

1. On the left-hand side use: "The product of a constant by a logarithm is equal to the logarithm raised to the constant"

Thus, the left-hand side is:

$2\log_9 x=\log_9 x^2$

2. On the right-hand side use "The sum of two logarithms with the same base is the logarithm of the product":

Then, on the right-hand side:

$\log_9 8+\log_9 (x-2)=\log_9 8(x-2)$

3. Make them equal:

$\log_9 x^2=\log_9 8(x-2)$

4. Since the two functions are the same, make the arguments equal:

$x^2=8(x-2)$

5. Solve the equation:

$x^2=8x-16\\\\x^2-8x+16=0\\\\(x-4)^2=0\\\\x-4=0\\\\x=4\leftarrow solution$

4 0

3 years ago

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