Y=35
Z=112
Hope this helps you and you have a good day and yes I did calculate this
Answer:
Hello some parts of your question is missing below is the missing part
answer : A) p-value = 0.0019 ,
The level of significance ( 0.05 ) > p-value ( 0.0019 )
B) There is no dependence between the two ratings
Step-by-step explanation:
A) using a 0.05 level of significance and test for independence of the quality of management
Test statistic :
∑ ( Oi - Ei )^2 / Ei
= [(40-35)^2 / 35 ] + [(25-24.5)^2 / 24.5 ] + [(5-10.5)^2 / 10.5] + [(35-40)^2 / 40] + [(35-28)^2 / 28] + [(10-12)^2 / 12] + [ (25-25)^2 / 25 ] + [(10-17.5)^2 / 17.5 ] + [(15-7.5)^2 / 7.5] = 17.03
p-value = 0.0019
Df = 4 ,
The level of significance ( 0.05 ) > p-value ( 0.0019 )
B) There is no dependence between the two ratings
Answer:
C) -9.6
Step-by-step explanation:
Answer:
Following are the solution to the given question:
Step-by-step explanation:
Please find the complete question in the attached file.

The total number of aces is approximately 167, 12 or more. The SE is 12 out of 1000, which is 1.2 percent.
The percentage of aces is expected to be around 16.67% , or 1.2%.