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Shtirlitz [24]
3 years ago
9

The variables A, B, and C represent polynomials where A=x^2, B=3x+2, and C=x-3. What is AB-C^2 in simplest form?

Mathematics
2 answers:
yuradex [85]3 years ago
7 0

Answer:

AB-C^2 = 3x^3 + x^2 + 9

Step-by-step explanation:

Hi

AB = (x^2)*(3x+2)= 3x^3 + 2x^2

C^2= (x-3)^2 = x^2 - 9

So

AB-C^2 = 3x^3 + 2x^2 - x^2 + 9 = 3x^3 + x^2 + 9

Natalija [7]3 years ago
7 0

The simplest form of AB-C^{2} is 3x^{3} +x^{2} +6x-9.

Step-by-step explanation:

Given,

A = x^{2}

B = 3x+2

C = x-3

To find,

AB-C^{2}

Putting the values of A, B, C we get

AB-C^{2}

= x^{2} (3x+2) - (x-3)^{2}

= 3x^{3} +2x^{2} -(x^{2} -6x+9)

= 3x^{3}+2x^{2}  -x^{2} +6x-9

=3x^{3} +x^{2} +6x-9

Here is the answer.

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