Question

The variables A, B, and C represent polynomials where A=x^2, B=3x+2, and C=x-3. What is AB-C^2 in simplest form?

Answer 1

Answer:

AB-C^2 = 3x^3 + x^2 + 9

Step-by-step explanation:

Hi

AB = (x^2)*(3x+2)= 3x^3 + 2x^2

C^2= (x-3)^2 = x^2 - 9

So

AB-C^2 = 3x^3 + 2x^2 - x^2 + 9 = 3x^3 + x^2 + 9

Answer 2

The simplest form of AB-$C^{2}$ is $3x^{3} +x^{2} +6x-9$.

Step-by-step explanation:

Given,

A = $x^{2}$

B = $3x+2$

C = $x-3$

To find,

AB-$C^{2}$

Putting the values of A, B, C we get

AB-$C^{2}$

= $x^{2} (3x+2) - (x-3)^{2}$

= $3x^{3} +2x^{2} -(x^{2} -6x+9)$

= $3x^{3}+2x^{2} -x^{2} +6x-9$

=$3x^{3} +x^{2} +6x-9$

Here is the answer.