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Tresset [83]
4 years ago
9

Determine the domain of (f/g)(x) when f (x)=1/x and g (x)=sqrtx+5

Mathematics
1 answer:
mash [69]4 years ago
5 0

we are given

f(x)=\frac{1}{x}

g(x)=\sqrt{x+5}

Calculation of (f/g)(x):

(\frac{f}{g})(x)=\frac{f(x)}{g(x)}

now, we can plug values

(\frac{f}{g})(x)=\frac{\frac{1}{x}}{\sqrt{x+5}}

now, we can simplify it

(\frac{f}{g})(x)=\frac{1}{x\sqrt{x+5}}

Domain:

we know that domain is all possible values of x for which any function is defined

function will be undefined when denominator =0

x\sqrt{x+5} =0

x=-5,x=0

we are given sqrt function

and we know that value inside sqrt will always be greater than 0

x+5>0

x>-5

so, domain will be

(-5,0)U(0,\infty)..............Answer

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Please answer this question now
xz_007 [3.2K]

Answer:

397.7 m²

Step-by-step Explanation:

Step 1: find m < W

W = 180 - (33+113) (sum of ∆)

W = 34°

Step 2: find side UV using the law of sines

\frac{UV}{sin(W)} = \frac{VW}{sin(U)}

\frac{UV}{sin(34)} = \frac{29}{sin(33)}

Multiply both sides by sin(34)

\frac{UV}{sin(34)}*sin(34) = \frac{29}{sin(33)}*sin(34)

UV = \frac{29*sin(34)}{sin(33)}

UV = 29.8 m (approximated)

Step 3: find the area using the formula, ½*UV*VW*sin(V)

area = ½*29.8*29*sin(113)

Area = 397.7 m² (rounded to the nearest tenth.

7 0
3 years ago
(-4x-2)+1/2(12x-22) simplify
Ierofanga [76]

Answer:

2x - 13

Step-by-step explanation:

Step  1  :

           1

Simplify   —

           2

Equation at the end of step  1  :

               1

 (-4x - 2) +  (— • (12x - 22))

               2

Step  2  : Pulling out like terms :

3.1     Pull out like factors :

  12x - 22  =   2 • (6x - 11)  

Step  3  :

Pulling out like terms :

3.1     Pull out like factors :

  12x - 22  =   2 • (6x - 11)  

Equation at the end of step  3  :

 (-4x - 2) +  (6x - 11)

6 0
3 years ago
Using a simulator at space​ camp, you practice landing your individual spaceship on landing platforms that have different shapes
Mila [183]

The Area of the platform is 33m²

Step-by-step explanation:

As the question says, the height of vertex from the base (D from AB) is 7m whereas the height of left vertex from the base (E from AB) is 4m

Thus it means the height of the Δ DCE (DX)= 7-4 ⇒3m

Since the platform is five-sided, the figure can be broken down into constituting parts

  1. Parallelogram ║ABCE
  2. Δ DCE

Are of the figure= Area of ║ABCE+ area Δ DCE

Area of ║ABCE= breadth * height

= 6*4 ⇒24m ²

Area Δ DCE= ½*(base)(height)

Putting the value of base is 6m and height as 3m

Area Δ DCE= ½*6*3

=9m ²

Total area= 24+9= 33m ²

3 0
3 years ago
I need help fastttt pleaseeeee
pogonyaev

Answer:

1, x = 80

2, z = 5.6

3, w = 18

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Find the area of the regular trapezoid. The figure is not drawn to scale. The top side is 4, the bottom side is 7, and both side
svp [43]
A regular trapezoid is shown in the picture attached.

We know that:
DC = minor base = 4
AB = major base = 7
AD = BC = lateral sides or legs = 5

Since the two legs have the same length, the trapezoid is isosceles and we can calculate AH by the formula:

AH = (AB - DC) ÷ 2
      = (7 - 5) ÷ 2
      = 2 ÷ 2
      = 1

Now, we can apply the Pythagorean theorem in order to calculate DH:
DH = √(AD² - AH²) 
      = √(5² - 1²)
      = √(25 - 1)
      = √24
      = 2√6

Last, we have all the information needed in order to calculate the area by the formula:

A =  \frac{(AB + CD)DH}{2}

A = (7 + 5) × 2√6 ÷ 2
   = 12√6

The area of the regular trapezoid is 12√6 square units.

7 0
3 years ago
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