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Probability that the first 2 of the friends to show up to the movie are friends he has known since kindergarten but the third not is 1/10
Total friends = 10
Friends from kindergarten = 4
Probability is the chance that a given event will occur. Probability of an event lies within 0 to 1
P(E) = Favourable outcomes / Total outcomes
Probability of getting 1st friend from kindergarten = 4/10
Probability of getting 2nd friend from kindergarten = 3/9
Probability of getting 3rd friend not from kindergarten = 6/8
Since all these probabilities are independent, We can use Multiplicative identity. Thus,
Required probability is 4/10 * 3/9 * 6/8
= 1/10
Thus, Probability that the first 2 of the friends to show up to the movie are friends he has known since kindergarten but the third not is 1/10
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All it is asking is to plug the given x values into the equation (which are 0, 2, 4) and see what you get for y.
4y - 2x =16
4y - 2 (0) = 16
4y = 16
y = 4
4y - 2 (2) = 16
4y - 4 = 16
4y = 20
y = 5
4y - 2 (4) = 16
4y - 8 = 16
4y = 24
y = 6
so D
Answer: x-7
Step-by-step explanation:
You can put h on -1 and sum on 0.4. Also, you put 1.4 in the wrong place. It should be three more places to the right.
